sql - 选择A列相同但B列不同的行

Question

ID          Zip        Room
----------- ---------- ------
317         94087      S105
318         94087      L603
1739        94404-1801 L603
1823        94401-2129 L603
1824        94401-2129 L603
2135        94404-1801 L603
2268        95136-1459 S604
2269        95136-1459 S604
3704        92673-6417 L402
4479        93454-9670 L402
4480        93454-9670 L402
4782        92395-4681 L402
4783        92395-4681 L402
4852        92886-4411 L402
4853        92886-4411 L402
4959        92673-6417 L402
5153        91773-4028 L402
5202        91773-4028 L402
5211        91765-2959 L402
5212        91765-2959 L402
5388        92336-0605 L402
5392        92336-0605 L402
5727        92870      L402
5728        92870      L402
5831        92557      L402
5916        92557      L402

如何选择具有相同拉链但房间不同的 ID？

在上表中，我希望结果为：

ID          Zip        Room
----------- ---------- ------
317         94087      S105
318         94087      L603

使用 SQL Server 2008

Answer 1

您可以使用EXISTS：

SELECT ID, Zip, Room 
FROM dbo.Table t1
WHERE EXISTS
(
   SELECT 1 FROM dbo.Table t2
   WHERE t2.Zip = t1.Zip
   AND t2.Room <> t1.Room
)

Answer 2

select * 
from table t1 
join table t2 
  on t1.Zip = t2.Zip and t1.Room <> t2.Room

Answer 3

您可以使用窗口聚合函数MIN()并MAX()相应地获取最小值和最大值Roomper Zip，然后仅选择这些值不同的行。这里：

WITH MinMax AS (
  SELECT
    *,
    MinRoom = MIN(Room) OVER (PARTITION BY Zip),
    MaxRoom = MAX(Room) OVER (PARTITION BY Zip)
  FROM atable
)
SELECT
  ID,
  Zip,
  Room
FROM MinMax
WHERE MinRoom <> MaxRoom
;