我正在为 Python 上的 End View 拼图开发求解器。这就是我到目前为止所拥有的。我很抱歉代码混乱，但我是新来的。我的问题是规则。整代和运行等工作正常。
有人可以给我任何建议或帮助考虑规则吗？
import re
import sys
katia=0
def read_data(filename):
try: f = open(filename, "r")
except:
print "\nERROR: File %s not found.\nNow try to open input.txt..." % filename
try:
f = open("input.txt", "r")
except:
print "\nERROR: File 'input.txt' not found."
sys.exit(raw_input("Press enter to exit..."))
return [ map(int, condition) for condition in
[ re.findall(r'\d+', line) for line in f.readlines()]
#here comes the rules in which i am not sure
def check(tab, row, conditions):
# check left-side conditions
if (conditions[0][row] != 0):
if ( ( tab[row][0] != conditions[0][row]
and
tab[row][1] != conditions[0][row]
and
tab[row][2] !=conditions[0][row]
)
or
( tab[row][1] == conditions[0][row]
and
tab[row][0] != 0
)
or
( tab[row][2] == conditions[0][row]
and
(tab[row][0] != 0 or tab[row][1] != 0)
)
):
return 0
# right-side conditions
if (conditions[1][row] != 0):
if( ( tab[row][-1] != conditions[1][row]
and
tab[row][-2] != conditions[1][row]
and
tab[row][-3] !=conditions[1][row]
)
or
( tab[row][-2] == conditions[1][row]
and
tab[row][-1] != 0
)
or
( tab[row][-3] == conditions[1][row]
and
( tab[row][-1] != 0 or tab[row][-2] != 0)
)
):
return 0
if row < (len(tab) - 3): # chek 3 below rows to uniqueness for uper numbers
for i in range(len(tab)):
if conditions[3][i] != 0:
if tab[row][i]==conditions[3][i]:
return 0
# check top-side conditions
if row == 1:
for col in range(len(tab)):
if conditions[2][col] != 0 :
if ( tab[1][col] == conditions[2][col]
and
( tab[2][col] == conditions[2][col]
and
tab[0][col] != 0 or tab[0][col] != 7
and
tab[1][col] != 0 or tab[1][col] != 7 )
or
( tab[0][col] != conditions[2][col]
and tab[1][col] != conditions[2][col]
and tab[2][col] != conditions[2][col] )
):
return 0
if row == 2:
for col in range(len(tab)):
if conditions[2][col] != 0:
if ( tab[1][col] != conditions[2][col]
and
tab[2][col] != conditions[2][col]
):
return 0
# check bottom-side conditions
if row == len(tab)-2:
for col in range(len(tab)):
if conditions[3][col] != 0:
if ( ( tab[-1][col] != conditions[3][col]
)
or
( tab[-2][col] == conditions[3][col]
and
tab[-1][col] == 0
)
):
return 0
if row == len(tab)-3:
for col in range(len(tab)):
if conditions[3][col] != 0:
if ( tab[-3][col] != conditions[3][col]
and
tab[-1][col] == 0
and
tab[-2][col] == 0
):
return 0
global katia
katia+=1
# check cols
for col in range(len(tab)):
for digit in range(1,4):
if( ([tab[i][col] for i in range(len(tab))].count(digit) > 1)
):
if katia%5000 == 0:
print "errrrror in %d: " % col,
print [tab[i][col] for i in range(len(tab))]
return 0
for col in range(len(tab)):
for digit in range(len(tab)):
if (( [tab[i][col] for i in range(len(tab))].count(digit)==0
and digit != 0 and digit !=7)
or
([tab[i][col] for i in range(len(tab))].count(digit) > 1
and digit not in range(1,7))
or
([tab[i][col] for
i in range(len(tab))].count(0)+ [tab[i][col]
for i in range(len(tab))].count(7) != 2)
):
return 0
katia++1
if katia/500 == 0:
for i in range(7):
print tab[i]
return 1
def generate(row):
if (row[0] == -1):
row[:] = range(len(row))
return 1
a = -1
for j in reversed(range(len(row)-1)):
if (row[j] < row[j+1]):
a = j
break
if a == -1:
return 0
b = -1
for j in reversed(range(a, len(row))):
if (row[j] > row[a]):
b = j
break
row[a], row[b] = row[b], row[a]
row[(a+1):] = reversed(row[(a+1):])
return 1
def rekurs(tab, row, conditions):
while (1):
if (generate(tab[row]) == 0):
tab[row] = [-1 for i in range( len(tab) )]
return 0
if check(tab, row, conditions) == 1:
if row < 7:
if (rekurs(tab, row+1, conditions)):
return 1
else:
return 1
## -------------------- run program -------------------
if __name__ == '__main__':
conditions = read_data(raw_input("Input file: "))
tab = [ [-1 for j in range(len(conditions[0]))]
for i in range( len(conditions[0]) ) ]
print "\nSuccess. \nNow search for solutions..."
if rekurs(tab, 0, conditions) == 0:
print "\nThere is no solution:"
for i in range(len(tab)): print tab[i]
else:
print "\nGood news:"
for i in range(len(tab)): print tab[i]
raw_input("Press enter to exit...")
运行代码后，您必须添加输入文件的名称，其中应包含限制：
0 4 2 6 1 0 5 0
0 6 5 0 5 4 3 0
0 1 6 2 3 2 0 0
1 3 5 4 2 3 6 6