4

我正在使用 OAuth-Sample-Client 代码通过 Linked Invitation API 从电子邮件地址发送邀请。我创建了与开发人员站点中描述的相同的主体，但现在我收到 401 错误，我已经搜索了很多，但没有得到任何解决方案让我从任何站点或论坛中摆脱它。我的回复如下。

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<error>
  <status>401</status>
  <timestamp>1351159386437</timestamp>
  <request-id>YX4NRU3S7J</request-id>
  <error-code>0</error-code>
  <message>[unauthorized]. OAU:ron8e8nko3te|e0a96317-dfdc-44fb-b427-5655e02f97ed|*01|*01:1351159294:dRCDN6b3K9F/mwWAaByKZQPgeVw=</message>
</error>

这里我的 json 字符串是这样的：

{"body":"说是！","subject":"连接邀请。","re​​cipients":{"values":[{"person":{"first-name":"test","last -name":"test","_path":"/people/email=test@test.com"}}]},"item-content":{"invitation-request":{"connect-type":"朋友”}}}

我已使用以下代码发送邀请。

- (IBAction)postButton_TouchUp:(UIButton *)sender
{    
    [statusTextView resignFirstResponder];
    NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/mailbox"];
    OAMutableURLRequest *request = 
    [[OAMutableURLRequest alloc] initWithURL:url
                                    consumer:oAuthLoginView.consumer
                                       token:oAuthLoginView.accessToken
                                    callback:nil
                           signatureProvider:[[OAHMAC_SHA1SignatureProvider alloc] init]];


    [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];

    NSDictionary *temp=[[NSDictionary alloc]initWithObjectsAndKeys:@"/people/email=test@test.com",@"_path",@"test",@"first-name",@"test",@"last-name", nil];
    NSDictionary *temp2=[[NSDictionary alloc] initWithObjectsAndKeys:temp,@"person",nil];
    NSArray *arr2=[[NSArray alloc]initWithObjects:temp2, nil];
    NSDictionary *value=[[NSDictionary alloc]initWithObjectsAndKeys:arr2,@"values", nil];
    NSDictionary *dict3=[[NSDictionary alloc]initWithObjectsAndKeys:@"friend",@"connect-type",nil];
    NSDictionary *dict4=[[NSDictionary alloc] initWithObjectsAndKeys:dict3,@"invitation-request", nil];
    NSDictionary *dict=[[NSDictionary alloc]initWithObjectsAndKeys:dict4,@"item-content",@"Say yes!",@"body",@"Invitation to connect.",@"subject",value,@"recipients", nil];
    NSLog(@"%@",[dict description]);
    NSString *updateString = [dict JSONString];
    [request setHTTPBodyWithString:updateString];
    [request setHTTPMethod:@"POST"];

    OADataFetcher *fetcher = [[OADataFetcher alloc] init];
    [fetcher fetchDataWithRequest:request
                         delegate:self
                didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
                  didFailSelector:@selector(postUpdateApiCallResult:didFail:)];    
    [request release];
}

我被困在这一点上，请让我摆脱困境。-提前致谢

4

3 回答 3

3

手动调用 OADataFetcher 的 prepare 方法。只需在设置请求正文之前放置即可。

[request prepare];
[request setHTTPBodyWithString:updateString];

这对我有用。当您使用 Invitation API 时，还要从 OADataFetcher 中删除 prepare 方法。

于 2012-10-25T11:45:01.743 回答
0

苹果的代码有效！还有一件事，不要忘记任何标题。我仍然收到相同的消息，结果我忘记添加 x-li-format 和 Content-type 标头。

于 2012-11-23T15:10:21.010 回答
0

我从这个Linkedin 线程得到了解决方案

您只需要对代码进行一些更改：

NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/mailbox"];

    OAMutableURLRequest *request =
    [[OAMutableURLRequest alloc] initWithURL:url
    consumer:oAuthLoginView.consumer
    token:oAuthLoginView.accessToken
    callback:nil
    signatureProvider:nil];
    [request setHTTPMethod:@"POST"];
    NSString *messageToPerson = @"/people/email=target@gmail.com";
    NSDictionary *person = [[NSDictionary alloc] initWithObjectsAndKeys:[[[NSDictionary alloc] initWithObjectsAndKeys:messageToPerson,@"_path",@"TargetFirstName",@"first-name",@"TargetSecondName",@"last-name",nil] autorelease], @"person",nil]; 
    NSArray *valueArray = [[NSArray alloc] initWithObjects:person,nil];
    NSDictionary *values = [[NSDictionary alloc] initWithObjectsAndKeys:valueArray,@"values", nil];
    NSDictionary *ir = [[NSDictionary alloc] initWithObjectsAndKeys:[[[NSDictionary alloc] initWithObjectsAndKeys:@"friend",@"connect-type",nil] autorelease], @"invitation-request",nil];
    NSDictionary *ic = [[NSDictionary alloc] initWithObjectsAndKeys:ir,@"item-content", nil];
    NSDictionary *update = [[NSDictionary alloc] initWithObjectsAndKeys:values,@"recipients",@"Invitation",@"subject",@"ConnectWithMe",@"body", ir, @"item-content", nil];
    [request setValue:@"json" forHTTPHeaderField:@"x-li-format"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
    NSLog(@"%@",[update description]);
    NSString *updateString = [update JSONString];

    [request prepare];

    [request setHTTPBodyWithString:updateString];

    OADataFetcher *fetcher = [[OADataFetcher alloc] init];
    [fetcher fetchDataWithRequest:request delegate:self
            didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
            didFailSelector:@selector(postUpdateApiCallResult:didFail:) withId:1];

    [request release];

并且在oAdata OADataFetcher.m

- (void)fetchDataWithRequest:(OAMutableURLRequest *)aRequest delegate:(id)aDelegate didFinishSelector:(SEL)finishSelector didFailSelector:(SEL)failSelector  withId:(int)idtm
        {

        [request release];
        
request = [aRequest retain];

        delegate = aDelegate;
        
didFinishSelector = finishSelector;

        didFailSelector = failSelector;

//note this change

        if (idtm!=1) {
   
        [request prepare];
        
       }

connection = [[NSURLConnection alloc] initWithRequest:aRequest delegate:self];
        
}


试试这个。肯定会工作。希望这将有助于未来的游客。

问候

于 2013-04-10T07:02:43.563 回答