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我有关于共享点应用程序的基本问题。

MS 提供了一些 Web 服务来访问共享点服务。

让我们以 GetListItems 服务为例。

我想知道，如何从 XML 解析器中识别项目是文件夹还是文件？我应该查看什么标签以将项目识别为文件夹或文件

如何获取文件或文件夹的属性（最后访问日期、只读等）。

请指导我正确的方向。

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1 回答 1

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Web 服务的典型响应如下所示：

<rs:data ItemCount="4">
  <z:row ows_Modified="2012-05-31 12:34:01" ows_ContentTypeId="0x01200082B0C5829FE047A1BF58F68DA1DAB12500C7BCD99F82ACA340A0131D59CE62371B" ows__ModerationStatus="0" ows__Level="1" ows_ID="1" ows_Created_x0020_Date="1;#2012-05-31 12:34:01" ows_PermMask="0x7fffffffffffffff" ows_FileRef="1;#depts/it/Lists/CTADocuments/mygroup" />
  <z:row ows_Modified="2012-05-31 12:36:51" ows_ContentTypeId="0x01200082B0C5829FE047A1BF58F68DA1DAB12500C7BCD99F82ACA340A0131D59CE62371B" ows__ModerationStatus="0" ows__Level="1" ows_ID="2" ows_Created_x0020_Date="2;#2012-05-31 12:36:51" ows_PermMask="0x7fffffffffffffff" ows_FileRef="2;#depts/it/Lists/CTADocuments/mygroup/another one" />
  <z:row ows_Modified="2012-05-31 17:49:45" ows_ContentTypeId="0x010100EB5D8789C471B04E80E2A7481607C23B" ows__ModerationStatus="0" ows__Level="1" ows_ID="9" ows_Created_x0020_Date="9;#2012-05-31 17:49:45" ows_PermMask="0x7fffffffffffffff" ows_FileRef="9;#depts/it/Lists/CTADocuments/Just_the_Essentials_Publishing.master" />
  <z:row ows_Modified="2012-06-07 17:05:11" ows_ContentTypeId="0x010100EB5D8789C471B04E80E2A7481607C23B" ows__ModerationStatus="0" ows__Level="1" ows_ID="10" ows_Created_x0020_Date="10;#2012-06-07 17:05:11" ows_PermMask="0x7fffffffffffffff" ows_FileRef="10;#depts/it/Lists/CTADocuments/mygroup/another one/junk.txt" />
</rs:data>

前两个 z:row 是文件夹（查看 ContentTypeId），其他是文档。

ContentTypeIds：http: //msdn.microsoft.com/en-us/library/aa543822.aspx

于 2012-10-24T17:01:33.040 回答