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几天来，我一直在尝试如何将图像上传到 API。那里有一个像这样的 cURL 示例。

curl "http://address.com/api/" -F "parameter[name]=My Upload" -F "parameter[description]=this is my upload" -F "parameter[other]=additional info" -F "parameter[image]=@wake_2560x1600.jpg;type=image/jpg"

我将如何使用它通过 NSMutableURLRequest 和 NSURLConnection 上传到服务器？我尝试了几种不同的方法，但都没有成功。有人有想法么？

编辑：

我目前正在尝试 ASIFormDataRequest

NSData *imageData = UIImageJPEGRepresentation(image, 0.9);
ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];
[request setDelegate:self];
[request addRequestHeader:@"User-Agent" value:@"iOS App"];
[request addPostValue:@"name" forKey:@"parameter[name]"];
[request addPostValue:@"description" forKey:@"parameter[description]"];
[request addPostValue:@"other" forKey:@"parameter[other]"];
[request addData:imageData withFileName:[NSString stringWithFormat:@"jpeg_%d.jpg", rand()] andContentType:@"image/jpeg" forKey:@"param[image]"];
[request startAsynchronous];
4

1 回答 1

2

粗略的做法。

PHP 脚本。

<?php
$target_path  = "./";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
 echo "The file ".  basename( $_FILES['uploadedfile']['name']).
 " has been uploaded";
} else{
 echo "There was an error uploading the file, please try again!";
}
?>

IOS代码

- (void)upload:(UIImage *)image {
    NSData *imageData = UIImageJPEGRepresentation(image, 80);
    NSString *urlString = @"http://www.upload.com/upload.php"; // URL of upload script.

    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
    [request setURL:[NSURL URLWithString:urlString]];
    [request setHTTPMethod:@"POST"];

    NSString *boundary = @"---------------------------14737809831466499882746641449";
    NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@", boundary];
    [request addValue:contentType forHTTPHeaderField:@"Content-Type"];

    NSMutableData *body = [NSMutableData data];
    [body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];
    [body appendData:[@"Content-Disposition: form-data; name=\"uploadedfile\"; filename=\"test.jpg\"\r\n" dataUsingEncoding:NSUTF8StringEncoding]];
    [body appendData:[@"Content-Type: application/octet-stream\r\n\r\n" dataUsingEncoding:NSUTF8StringEncoding]];
    [body appendData:[NSData dataWithData:imageData]];
    [body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];
    [request setHTTPBody:body];

    NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
    NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
    NSLog(@"returnString: %@", returnString);
}

只需确保您使用的变量名相同，在这里我对 php 和 ioscode 都使用“uploadedfile”

php

if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path))

IOS 

[body appendData:[@"Content-Disposition: form-data; name=\"uploadedfile\"; filename=\"test.jpg\"\r\n" dataUsingEncoding:NSUTF8StringEncoding]];

// 虽然现在我使用https://github.com/samvermette/SVHTTPRequest

如果您在代码中导入该库，那么上传将像这样简单

[SVHTTPRequest POST:@"http://www.upload.com/upload.php"
            parameters:[NSDictionary dictionaryWithObjectsAndKeys:imageData, @"uploadedfile", nil]
              progress:^(float progress) {
                  progressLabel.text = [NSString stringWithFormat:@"Uploading (%.0f%%)", progress*100];
              }
            completion:^(id response, NSHTTPURLResponse *urlResponse, NSError *error) {
                progressLabel.text = @"Upload complete";
            }];
于 2013-03-15T08:14:53.057 回答