mysql - mysql - 过滤 IN 语句

Question

我需要细化这个 sql 选择：

SELECT ch_num, payment_type, Total FROM transactions WHERE ( ch_num ) 
IN (
SELECT ch_num FROM transactions GROUP BY ch_num HAVING count('ch_num') > 1 
)
ORDER BY `ch_num`

我得到的结果是：

ch_num  payment_type    Total 
20001   visa        36.60
20001   visa        36.60
20001   mc          30.60
50019   cash        9.00
50019   mc          18.95
50023   cash        2.70
50023   visa        7.00

但我只需要有'cash' payment_type 的结果行，所以'ch_no' 20001 应该被省略。正确的结果是：

ch_num  payment_type    Total 
50019   cash        9.00
50019   mc          18.95
50023   cash        2.70
50023   visa        7.00

Answer 1

SELECT ch_num, payment_type, Total
FROM transactions 
WHERE ch_num IN 
(
       SELECT ch_num 
       FROM transactions 
       GROUP BY ch_no
       HAVING count('ch_num') > 1 
       and sum(payment_type='cash') >= 1
)
ORDER BY `ch_num`

Answer 2

这是一个完整的、经过验证的代码示例，最后附有测试结果。我使用了 Oracle，但 SQL SELECT 的语法应该相同。

create table transactions (ch_num int, payment_type varchar2(100), total float);

insert into transactions values(20001,'visa',36.60);
insert into transactions values(20001,'mc',30.60);
insert into transactions values(50019,'cash',9.00);
insert into transactions values(50019,'mc',18.95);
insert into transactions values(50023,'cash',2.70);
insert into transactions values(50023,'visa',7.00);

SELECT ch_num, payment_type, Total FROM transactions a WHERE ( ch_num ) 
IN (
SELECT ch_num FROM transactions  GROUP BY ch_num HAVING count(ch_num) > 1 
)
AND EXISTS
(SELECT  ch_num FROM transactions b where payment_type = 'cash' and a.ch_num = b.ch_num)
ORDER BY ch_num

结果：

    CH_NUM  PAYMENT_TYPE    TOTAL
1   50019   cash    9
2   50019   mc  18.95
3   50023   cash    2.7
4   50023   visa    7