我是 ios 新手,正在尝试做这样的事情
self.dataArray = [dictionary valueForKey:@"LIST"];
{
"List": [
{
"FULLNAME": "FirstName, LastName",
"ID": "281"
}
]
}
我想交换“全名”中的值,即我希望它是姓氏,名字
我尝试了各种方法,但都行不通。有人能告诉我如何做到这一点吗?
谢谢
我是 ios 新手,正在尝试做这样的事情
self.dataArray = [dictionary valueForKey:@"LIST"];
{
"List": [
{
"FULLNAME": "FirstName, LastName",
"ID": "281"
}
]
}
我想交换“全名”中的值,即我希望它是姓氏,名字
我尝试了各种方法,但都行不通。有人能告诉我如何做到这一点吗?
谢谢
假设您知道如何进行字典操作,这里有一种交换字符串中元素的方法:
NSString* name = @"Firstname, Lastname";
// Remove the space after comma (not necessary if you know the name will always
// have a space after comma, then just split on ', '.
NSString* normalizedName = [name stringByReplacingOccurrencesOfString:@", " withString:@","];
// Split the string on ','.
NSArray* nameParts = [normalizedName componentsSeparatedByString:@","];
// Reverse the array
NSArray* reverseNameParts = [[nameParts reverseObjectEnumerator] allObjects];
// Join the array with ', '
NSString* revname = [reverseNameParts componentsJoinedByString:@", "];
NSLog(@"Reversed name parts: %@", revname);
如果您的字典包含数组,我相信它应该是 objectForKey 而不是 valueForKey。
self.dataArray = [dictionary objectForKey:@"LIST"];
for(NSString *fullname in self.dataArray){
if([fullname isEqualToString:@"FULLNAME"]){
NSArray *name = [fullname componentsSeparatedByString:@","];
NSMutableString* reverseName = [NSMutableString string];
for (int i=[name count]-1; i>=0;i--){
[reverseName appendFormat:@", ", [name objectAtIndex:i]];
//reverse name should be what you are looking for..or something close
}
}
}
希望这可以帮助