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我使用自定义适配器从列表中填充的 gridView 遇到了一个奇怪的问题。

一切看起来都很正常，直到 gridView 的第一页已满，然后一些后续项目丢失或不同步。

我做了两个屏幕截图，第一个是单列，第二个是两个。如您所见，第一页都正确呈现，如下图所示：

单栏：http ://screencast.com/t/mSoEsDf1cY

和

两栏：http ://screencast.com/t/i6zfPLYf

我简化了代码来演示这个问题：

public class Activity1 : Activity
{
    List<Item> _items = null;

    protected override void OnCreate (Bundle bundle)
    {
        base.OnCreate (bundle);

        // Set our view from the "main" layout resource
        SetContentView (Resource.Layout.Main);

        _items = new List<Item>();

        for ( int i =0; i < 30; i++)
        {
            Item newItem = new Item();
            newItem.Text = "Item " + i;
            newItem.Bitmap = Android.Graphics.BitmapFactory.DecodeResource( this.Resources, Resource.Drawable.Icon );

            _items.Add( newItem );
        }

        GridView grid = FindViewById<GridView> (Resource.Id.gridView1);
        grid.SetNumColumns(2);

        ItemGridViewAdapter adapter = new ItemGridViewAdapter( this, _items);
        grid.Adapter = adapter;
    }

}

public class Item
{
    public Android.Graphics.Bitmap Bitmap { get; set; }
    public string Text { get; set; }
}

public class ItemGridViewAdapter : BaseAdapter<Item>
{
    private List<Item> _items = null;
    private Context _context = null;

    public override int Count {
        get {
            return _items.Count;
        }
    }

    public override long GetItemId (int position)
    {
        return position;
    }

    public override Item this[int position] {
        get {
            return _items[position];
        }
    }

    public ItemGridViewAdapter (Context context, List<Item> items)
    {
        _items = items;
        _context = context;
    }

    public override View GetView (int position, View convertView, ViewGroup parent)
    {
        //based on http://developer.android.com/guide/topics/ui/layout/gridview.html

        RelativeLayout layout = null;

        if (convertView == null) {
            layout = new RelativeLayout( _context );

            RelativeLayout.LayoutParams rlp = new RelativeLayout.LayoutParams (RelativeLayout.LayoutParams.WrapContent, RelativeLayout.LayoutParams.WrapContent);

            ImageView image = new ImageView (_context);
            image.LayoutParameters = new Gallery.LayoutParams (150, 150);
            image.SetImageBitmap ( this[position].Bitmap );
            image.Id = 1;
            layout.AddView (image);

            RelativeLayout.LayoutParams title_lp = new RelativeLayout.LayoutParams (RelativeLayout.LayoutParams.WrapContent, RelativeLayout.LayoutParams.WrapContent);
            TextView title = new TextView (_context);
            title.Text = this[position].Text; 
            title.Id = 2;
            title.SetTextColor (Android.Graphics.Color.White);
            title_lp.AddRule (LayoutRules.RightOf, 1);
            title_lp.AddRule (LayoutRules.CenterVertical);
            layout.AddView (title, title_lp);

        } else {

            layout = (RelativeLayout)convertView;
        }

        return layout;
    }

}

任何想法将不胜感激。

4

1 回答 1

1

您的代码重用了一些随机的旧项目视图，而无需在此处进行任何修改：

    layout = (RelativeLayout)convertView;

您的 getView() 应该被修改以提供新的值，这些值是位置的函数，对于任何视图，无论是回收的还是刚刚创建的。

考虑这里的示例：http: //developer.android.com/guide/topics/ui/layout/gridview.html。

它们的作用与您在“其他”部分中所做的几乎相同。但在那之后，它们为视图提供了一个新的价值——在他们的例子中，一个新的图像：

} else {
    imageView = (ImageView) convertView;
}

// Analogous update is missing from your code.
// Set your view's image, text, etc. here:
imageView.setImageResource(mThumbIds[position]);

return imageView;
于 2012-10-15T21:59:23.263 回答