我正在一个 wordpress 网站上构建一个表格，该表格显示从一个表格中排序的数据。
我无法正确地将标题更改为 URL，该 URL 可以从同一个数据库中更改（slug）。
基本 url 保持不变，只有 slug 更改，即wwww.thesite.com/job/view/ --- 然后是 slug。
到目前为止，这是我的代码。
function dbTEST($atts, $content = null) {
// Get all the data from the "job board" table
$result = mysql_query("SELECT * FROM wpjb_job WHERE job_country='72' ORDER BY job_title")
or die(mysql_error());
echo "<table border='1'>";
echo "<tr> <th>Job</th> <th>Company</th> </tr>";
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result )) {
// Print out the contents of each row into a table
echo "<tr><td>";
#---------- I need this job_title to url link to the job_slug
echo $row['job_title'];
echo $row['job_slug'];
echo "</td><td>";
echo $row['company_name'];
echo "</td></tr>";
}
echo "</table>";
}