5

您好我正在尝试在 ListView 中创建 3 列。

我读了这个,但我想在 C# 中以编程方式设置每列中的数据:

如何在行和列中显示数据 XAML windows 8

例如,我想要艺术家姓名、歌曲名称和艺术家。

4

2 回答 2

7

假设你有这样的东西来存储你的数据:

public class SongDetails
{
    public string ArtistName {get; set;}
    public string SongName {get; set;}
    public string Artist {get; set;}
}

和一个定义了 DataTemplate 的 ListView(如您提供的链接中所示),只需给您的 ListView 一个名称:

<ListView Name="ListViewSongs">
    <ListView.ItemTemplate>
        <DataTemplate>
            <Grid Width="500" VerticalAlignment="Center">

                <Grid.ColumnDefinitions>
                    <ColumnDefinition Width="120" />
                    <ColumnDefinition Width="*" />
                    <ColumnDefinition Width="150" />
                </Grid.ColumnDefinitions>

                <TextBlock Grid.Column="0" Text="{Binding Artist}" />
                <TextBlock Grid.Column="1" Text="{Binding ArtistName}" />
                <TextBlock Grid.Column="2" Text="{Binding SongName}" />
            </Grid>
        </DataTemplate>
    </ListView.ItemTemplate>
</ListView>

然后,从后面的代码来看,这只是以下情况:

var songDetails = new[]
    {
        new SongDetails {Artist = "a1", ArtistName = "a2", SongName = "a3"},
        new SongDetails {Artist = "b1", ArtistName = "b2", SongName = "b3"}
    };

ListViewSongs.ItemsSource = songDetails;
于 2012-10-10T23:38:17.093 回答
4

如果您不想硬编码项目/网格的宽度(响应式设计),则改进了Seb Boulet 答案的XAML :

<ListView Name="ListViewSongs">
    <ListView.ItemContainerStyle>
        <Style TargetType="ListViewItem">
            <Setter Property="HorizontalContentAlignment" Value="Stretch"></Setter>
        </Style>
    </ListView.ItemContainerStyle>
    <ListView.ItemTemplate>
        <DataTemplate>
            <Grid>
                <Grid.ColumnDefinitions>
                    <ColumnDefinition Width="120" />
                    <ColumnDefinition Width="*" />
                    <ColumnDefinition Width="150" />
                </Grid.ColumnDefinitions>
                <TextBlock Grid.Column="0" Text="{Binding Artist}" />
                <TextBlock Grid.Column="1" Text="{Binding ArtistName}" />
                <TextBlock Grid.Column="2" Text="{Binding SongName}" />
            </Grid>
        </DataTemplate>
    </ListView.ItemTemplate>
</ListView>

相关主题:如何让 ListBox ItemTemplate 水平拉伸 ListBox 的整个宽度?

于 2016-03-16T20:30:28.800 回答