2

我想要做的是获取一个 JSON 提要,然后遍历结果。但是,当我从字典中获取对象时,我一直在获取字符串而不是数组。关于我做错了什么的任何想法?

这是 JSON:

[
  {
    "_id": "4f6d9a7c1d0b4900010007ee",
    "geo_triggers": [
      {
        "_id": "4fc3e5fdc7234e0001000002",
        "location": [1,1],
        "longitude": "1",
        "latitude": "1",
        "radius": 1,
        "location_name": "Test 1"
      },
      {
        "_id": "4fc61f3762f53f0001000043",
        "location": [-71.057673,42.355395],
        "longitude": "-71.057673",
        "latitude": "42.355395",
        "radius": 1000,
        "location_name": "Test2"
      }
    ]
  }
]

这是目标 C 代码:

const char* className = class_getName([result class]);
NSLog(@"Result is a: %s", className);
NSLog(@"%@", result); //string
NSArray* json = [result objectForKey:@"result"]; //should be an array of dictionaries
NSLog(@"JSON Output: %@", json);
const char* className1 = class_getName([json class]);
NSLog(@"yourObject is a: %s", className1);

这是输出:

Result is a: __NSDictionaryI
2012-10-10 17:15:15.165 App[12980:19d03] {
    result = "[{\"_id\":\"4f6d9a7c1d0b4900010007ee\",\"geo_triggers\":[{\"_id\":\"4fc3e5fdc7234e0001000002\",\"location\":[1.0,1.0],\"longitude\":\"1\",\"latitude\":\"1\",\"radius\":1,\"location_name\":\"Test 1\"},{\"_id\":\"4fc61f3762f53f0001000043\",\"location\":[-71.057673,42.355395],\"longitude\":\"-71.057673\",\"latitude\":\"42.355395\",\"radius\":1000,\"location_name\":\"Test2\"}]}]";
}
2012-10-10 17:15:15.166 App[12980:19d03] JSON Output: [{"_id":"4f6d9a7c1d0b4900010007ee","geo_triggers":[{"_id":"4fc3e5fdc7234e0001000002","location":[1.0,1.0],"longitude":"1","latitude":"1","radius":1,"location_name":"Test 1"},{"_id":"4fc61f3762f53f0001000043","location":[-71.057673,42.355395],"longitude":"-71.057673","latitude":"42.355395","radius":1000,"location_name":"Test2"}]}]
2012-10-10 17:15:15.166 App[12980:19d03] yourObject is a: __NSCFString
2012-10-10 17:15:15.166 App[12980:19d03] -[__NSCFString countByEnumeratingWithState:objects:count:]: unrecognized selector sent to instance 0xb331800
4

2 回答 2

6

您的result变量指向字典。字典包含一个键。那把钥匙是@"result"。该键的值是一个字符串,@"[{\"_id\":\"4f6d9a7c1d0b4900010...

换句话说,您还没有真正反序列化您的 JSON。您需要获取 key 的值result并通过 JSON 反序列化器运行它。

于 2012-10-10T21:32:44.240 回答
1

首先需要解码结果。以上是JSON,所以我建议这样做

  1. 如果您还没有它,请下载 JSONKit.h 并将其包含在您的项目中
  2. 然后你可以做

    1. NSString* json = [result JSONString];查看输出
    2. id jsonDict = [[JSONDecoder decoder] objectWithData:responseData]; 之后你可以做类似的事情 [jsonDict objectForKey:@"_id"]; ///ETC
于 2012-10-10T22:38:51.120 回答