c++ - gdb - 列出当前函数的源而不输入其名称

Question

在 GDB 中，命令：

list function

将列出该函数的所有源。

是否有一个命令可以列出您当前所在函数的所有源代码，而无需您手动输入函数名称？

Answer 1

(gdb) help list
List specified function or line.
With no argument, lists ten more lines after or around previous listing.
"list -" lists the ten lines before a previous ten-line listing.
One argument specifies a line, and ten lines are listed around that line.
Two arguments with comma between specify starting and ending lines to list.
Lines can be specified in these ways:
  LINENUM, to list around that line in current file,
  FILE:LINENUM, to list around that line in that file,
  FUNCTION, to list around beginning of that function,
  FILE:FUNCTION, to distinguish among like-named static functions.
  *ADDRESS, to list around the line containing that address.
With two args if one is empty it stands for ten lines away from the other arg.

这才*ADDRESS是有趣的。

在 x86/x64 上，当前指针在rip寄存器中，所以：

(gdb) list *$pc
0x7ffff7b018a0 is at ../sysdeps/unix/syscall-template.S:82.
77  in ../sysdeps/unix/syscall-template.S

该示例来自cat命令，因为我手头没有任何调试信息。

Answer 2

当您在函数类型bt中停止以进行回溯时。Backtrace 将列出当前堆栈。顶部的元素 #0 通常是您感兴趣的函数，并且还会列出源文件和行号。

例如：

(gdb) bt
#0  myClass::EntityTypeStruct::readAttributes (this=0x7fffd00066e0, buf=0x7fffd0006020 "", len=48)
    at /team/project/src/EntityTypeStruct.cc:55
#1  0x000000000044ca86 in workerThread (ts=0x7fffea71dcc0)
    at /team/project/src/threads/workerThread.cc:219
#2  0x00007ffff775e9d1 in start_thread () from /lib64/libpthread.so.0
#3  0x00007ffff6c07b5d in clone () from /lib64/libc.so.6

有关更多信息，请参见http://www.chemie.fu-berlin.de/chemnet/use/info/gdb/gdb_7.html#SEC42。

此外，当您设置断点时，您可以指定每次遇到该断点时都会运行的命令。见http://www.chemie.fu-berlin.de/chemnet/use/info/gdb/gdb_6.html#SEC35

因此，如果您知道函数中有多少行，您可以设置一个命令来列出函数的所有源代码行：

(gdb) break myClass::EntityTypeStruct::readAttributes
Breakpoint 1 at 0x61ec3b: file /team/project/src/EntityTypeStruct.cc, line 38.
(gdb) commands 1
list 38,104
end

Answer 3

gdbtui 可用于在调试期间查看源代码。

Answer 4

'frame' 命令显示函数名称和当前行位置，并将 list 的当前行设置为当前可执行行。

set listsize 17
frame
list

列出当前行周围的 8 行。