1

我为 Access DB 编写了这个查询。 

queryText = "SELECT Technicians.ID, firstName, lastName, Technicians.[Zone],
COUNT(technicianAssignedId) AS JobsDone, 
MAX(Faults.timeCompleted) AS LastJobTime,
MIN(Technicians.[Zone] - & faultZone &) AS Distance ' MIN has no use
FROM Technicians LEFT OUTER JOIN Faults ON
Technicians.ID = Faults.technicianAssignedID 
WHERE Specialization = '" & specialization & "'
`AND Availability = 'available' 
GROUP BY Technicians.ID, firstName, lastName, Availability,` Technicians.[Zone], Specialization 
ORDER BY 7 DESC"

我有这个来获得绝对值

SELECT CASE
WHEN value < 0 THEN value * -1
ELSE number *1 END
AS VALUE
FROM DB;

现在，具有距离别名的列可能会以负数结束，我需要使用 (* -1) 作为正数，但我不知道如何将它们组合在一起。

谢谢你的帮助

4

3 回答 3

5

尝试

ABS(Technicians.[Zone] - & faultZone &) AS Distance

参见ABS 文档

于 2012-10-09T17:26:50.330 回答
3

为什么不能只使用绝对函数，ABS？

于 2012-10-09T17:27:10.077 回答
1

ABS() 适用于所有 SQL 版本

于 2013-01-07T19:37:04.753 回答