27

如果一个JavaFX项目中有3个文件；FXML 文件、FXML 控制器和应用程序类；控制器如何通过更改该单击上的屏幕（通常使用 完成）来响应按钮单击（效果很好stage.setScreen()）？我没有提到舞台（它被传递给应用程序类start(Stage)）。

应用样本：

public class JavaFXApplication4 extends Application {

    @Override
    public void start(Stage stage) throws Exception {
        Parent root = FXMLLoader.load(getClass().getResource("Sample.fxml"));

        Scene scene = new Scene(root);

        stage.setScene(scene);
        stage.show();
    }

    /**
     * The main() method is ignored in correctly deployed JavaFX application.
     * main() serves only as fallback in case the application can not be
     * launched through deployment artifacts, e.g., in IDEs with limited FX
     * support. NetBeans ignores main().
     *
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        launch(args);
    }
}

FXML 示例：

<?xml version="1.0" encoding="UTF-8"?>

<?import java.lang.*?>
<?import java.util.*?>
<?import javafx.scene.*?>
<?import javafx.scene.control.*?>
<?import javafx.scene.layout.*?>

<AnchorPane id="AnchorPane" prefHeight="200.0" prefWidth="320.0"  xmlns:fx="http://javafx.com/fxml" fx:controller="javafxapplication4.SampleController">
  <children>
  <Button id="button" fx:id="nextScreen" layoutX="126.0" layoutY="90.0" onAction="#handleButtonAction" text="Next Screen" />
  <Label fx:id="label" layoutX="126.0" layoutY="120.0" minHeight="16.0" minWidth="69.0" />
  </children>
</AnchorPane>

控制器示例：

public class SampleController implements Initializable {

    @FXML
    private Label label;

    @FXML
    private void handleButtonAction(ActionEvent event) {
        System.out.println("You clicked me!");
        label.setText("Hello World!");

        // Here I want to swap the screen!
    }

    @Override
    public void initialize(URL url, ResourceBundle rb) {
        // ...
    }    
}
4

3 回答 3

41 
@FXML
private void handleButtonAction(ActionEvent event) {
    System.out.println("You clicked me!");
    label.setText("Hello World!");
    //Here I want to swap the screen!

    Stage stageTheEventSourceNodeBelongs = (Stage) ((Node)event.getSource()).getScene().getWindow();
    // OR
    Stage stageTheLabelBelongs = (Stage) label.getScene().getWindow();
    // these two of them return the same stage
    // Swap screen
    stage.setScene(new Scene(new Pane()));
}
于 2012-10-09T17:20:15.263 回答
18

我在进入 Java 并试图解决同样的问题时发现了这个老问题。因为我希望场景记住切换之间的内容，所以我不能使用接受的答案，因为在场景之间切换时它会再次实例化它们（失去它们以前的状态）。

无论如何，接受的答案和类似问题的答案给了我一个关于如何在不丢失状态的情况下切换场景的提示。主要思想是将场景的实例注入另一个控制器，这样控制器就不需要一遍又一遍地实例化一个新的场景，而是可以使用已经存在的实例（及其状态）。

所以这里是实例化场景的主类：

public class Main extends Application {

    public static void main(String[] args) {
        launch(args);
    }

    @Override
    public void start(Stage primaryStage) throws Exception {
        // getting loader and a pane for the first scene. 
        // loader will then give a possibility to get related controller
        FXMLLoader firstPaneLoader = new FXMLLoader(getClass().getResource("firstLayout.fxml"));
        Parent firstPane = firstPaneLoader.load();
        Scene firstScene = new Scene(firstPane, 300, 275);

        // getting loader and a pane for the second scene
        FXMLLoader secondPageLoader = new FXMLLoader(getClass().getResource("secondLayout.fxml"));
        Parent secondPane = secondPageLoader.load();
        Scene secondScene = new Scene(secondPane, 300, 275);

        // injecting second scene into the controller of the first scene
        FirstController firstPaneController = (FirstController) firstPaneLoader.getController();
        firstPaneController.setSecondScene(secondScene);

        // injecting first scene into the controller of the second scene
        SecondController secondPaneController = (SecondController) secondPageLoader.getController();
        secondPaneController.setFirstScene(firstScene);

        primaryStage.setTitle("Switching scenes");
        primaryStage.setScene(firstScene);
        primaryStage.show();
    }
}

这是两个控制器：

public class FirstController {

    private Scene secondScene;

    public void setSecondScene(Scene scene) {
        secondScene = scene;
    }

    public void openSecondScene(ActionEvent actionEvent) {
        Stage primaryStage = (Stage)((Node)actionEvent.getSource()).getScene().getWindow();
        primaryStage.setScene(secondScene);
    }
}

是的，第二个看起来一样（可能可以共享一些逻辑，但当前状态足以作为概念证明）

public class SecondController {

    private Scene firstScene;

    public void setFirstScene(Scene scene) {
        firstScene = scene;
    }

    public void openFirstScene(ActionEvent actionEvent) {    
        Stage primaryStage = (Stage)((Node)actionEvent.getSource()).getScene().getWindow();
        primaryStage.setScene(firstScene);
    }
}
于 2017-05-26T00:27:21.597 回答
2

你也可以这样试试。

public void onBtnClick(ActionEvent event) {
    try {
        FXMLLoader loader = new FXMLLoader(getClass().getResource("login.fxml"));
        Stage stage = (Stage) btn.getScene().getWindow();
        Scene scene = new Scene(loader.load());
        stage.setScene(scene);
    }catch (IOException io){
        io.printStackTrace();
    }

}
于 2018-02-16T09:28:42.367 回答