mysql - 如何对子查询使用删除语句 - 错误 1093？

Question

此查询准确返回我需要删除的办公室元组。

    SELECT id, reference FROM office o 
WHERE o.id NOT IN 
    (SELECT c.office_id FROM Contract c  WHERE office_id IS NOT NULL)
AND o.reference IN 
    (SELECT o.reference FROM Contract c JOIN office o ON c.office_id = o.id  WHERE office_id IS NOT NULL);

但是当我写查询

    DELETE FROM office 
WHERE id NOT IN 
    (SELECT c.office_id FROM Contract c  WHERE office_id IS NOT NULL)
AND reference IN 
    (SELECT o.reference FROM Contract c JOIN office o ON c.office_id = o.id  WHERE office_id IS NOT NULL);

我有以下错误：#1093 - You can't specify target table 'office' for update in FROM clause

但我真的不知道如何解决这个问题..

任何帮助将非常感激！

Answer 1

尝试

 DELETE FROM office 
 WHERE id NOT IN 
(SELECT c.office_id FROM Contract c
 WHERE office_id IS NOT NULL)
 AND reference IN 
(select * from (SELECT o.reference FROM Contract c 
 JOIN office o ON c.office_id = o.id 
 WHERE office_id   IS NOT NULL) x);

因为您无法从您选择的表中删除。但是使用

select * from (select col from your_table) x

应该做的伎俩