1

我想根据这种模式打印对象的数量:

If there is 1 object, print 0
If there is 2 objects, print 0 1
If there is 3 objects, print 0 1 2

我尝试了以下代码:

for($i = count($nodes) ; $i >= 0 ; $i--){
print $i;
}

但结果是:

If there is 1 object, print 0 1
If there is 2 objects, print 0 1 2
if there is 3 objects, print 0 1 2 3

我不能使用。我怎样才能做到这一点?

4

1 回答 1

3

你应该这样使用:

 $n = 3; // where n is no. of object
for($i=0; $i<$n; $i++){
    print $i." ";
    }
 //output 0 1 2
于 2012-10-06T04:05:03.737 回答