mysql - UPDATE table1 SET column1 = (SUM(table2{& table3} WHERE table2_id1 = id1) WHERE id1 = table2_id1

Question

我想根据主要应用于 table2 但包括表 3 中的单个值的总和来更新 table1。

table2 有一列是对 table1 的 id 列的 FKd，并且总和基于它们的匹配。

UPDATE table1, table2 
SET table1.column1 = 
(SELECT SUM( (SELECT constant FROM table3) +
          (SELECT table2.sum_number 
           WHERE table2.table2_id1 = table1.id) ) ) 
WHERE table1.id = table2.table2_id1;

这对我不起作用。

提前谢谢了！

编辑：给定错误

#1064 - You have an error in your SQL syntax; check the manual that corresponds 
 to your MySQL server version for the right syntax to use near 
 'WHERE table2.table2_id1 = table1.id) ) ) WHERE table1.id = table2.table2_id1;'

Answer 1

UPDATE table1, table2 
SET table1.column1 = 
(
    SELECT SUM( 
        (SELECT constant FROM table3) +
        (SELECT table2.sum_number *** WHERE table2.table2_id1 = table1.id) 
    ) 
) 
WHERE table1.id = table2.table2_id1;

上面标有星号的区域没有“FROM table2,table1”。

Answer 2

试试这个：

UPDATE 
    table1 t1
INNER JOIN
    table2 t2 ON t2.table2_id1 = t1.id
SET
    t1.column1 = (SELECT constant FROM table3) + t2.sum_number

Answer 3

试试这个：

Update table1 t1 join table2 t2 on t1.id = t2.table2_id1
SET t1.column1 = (SELECT constant FROM table3) + t2.sum_number