请帮助 Spring MVC 新手。我很难HandlerInterceptorAdapter工作。这是代码和配置文件。mvc-调度程序-servlet.xml：
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<mvc:annotation-driven />
<context:component-scan base-package="com.myproject" />
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping" >
<property name="interceptors">
<list>
<ref bean="loginInterceptor" />
</list>
</property>
</bean>
<bean id="loginInterceptor" class="com.myproject.util.login.LoginInterceptor" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver" >
<property name="prefix">
<value>/WEB-INF/pages/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
登录拦截器.java：
package com.myproject.util.login;
import org.apache.log4j.Logger;
import org.springframework.web.servlet.handler.HandlerInterceptorAdapter;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class LoginInterceptor extends HandlerInterceptorAdapter {
private static final Logger LOG = Logger.getLogger(LoginInterceptor.class);
@Override
public boolean preHandle(HttpServletRequest request, HttpServletResponse response, Object handler) throws Exception {
LOG.debug("intercepted");
return super.preHandle(request, response, handler);
}
}
我试图让这个拦截器为任何控制器运行。也许，ControllerClassNameHandlerMapping， 不是为此目的的最佳选择。请帮忙。