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就像一个应用程序为 iPad 和 iPhone 使用不同的故事板一样,我希望我的应用程序为 iPhone 5 使用不同的故事板。由于 Info.plist 中没有选择 iPhone 5 的默认故事板的选项,我将如何以编程方式调用故事板?

我不想为这个应用程序使用自动布局,除非它绝对是最后的手段。我了解如何检测用户是否使用 iPhone 5 或具有相同屏幕尺寸的其他设备。我只需要知道如何在没有 plist 的情况下设置默认情节提要。

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2 回答 2

56

几周前我一直在寻找相同的答案,这是我的解决方案,希望对您有所帮助..

-(void)initializeStoryBoardBasedOnScreenSize {

    if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
{    // The iOS device = iPhone or iPod Touch


    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;

    if (iOSDeviceScreenSize.height == 480)
    {   // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)

        // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35
        UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone35" bundle:nil];

        // Instantiate the initial view controller object from the storyboard
        UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];

        // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
        self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

        // Set the initial view controller to be the root view controller of the window object
        self.window.rootViewController  = initialViewController;

        // Set the window object to be the key window and show it
        [self.window makeKeyAndVisible];
    }

    if (iOSDeviceScreenSize.height == 568)
    {   // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)

        // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
        UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone4" bundle:nil];

        // Instantiate the initial view controller object from the storyboard
        UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];

        // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
        self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

        // Set the initial view controller to be the root view controller of the window object
        self.window.rootViewController  = initialViewController;

        // Set the window object to be the key window and show it
        [self.window makeKeyAndVisible];
    }

    } else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)

    {   // The iOS device = iPad

    UISplitViewController *splitViewController = (UISplitViewController *)self.window.rootViewController;
    UINavigationController *navigationController = [splitViewController.viewControllers lastObject];
    splitViewController.delegate = (id)navigationController.topViewController;

    }
}

在 AppDelegate ddiFinishLaunchingWithOptions: 方法下调用此方法并且也不要正确忘记故事板的名称

希望有帮助...

于 2012-10-02T18:48:51.923 回答
4

这对我有用 - 通过将故事板包装在一个函数中进行轻微改进

-(UIStoryboard*) getStoryboard {   
    UIStoryboard *storyBoard = nil;
    if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad) {         
        storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPad" bundle:nil];
    }else{
        if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone){
            // The iOS device = iPhone or iPod Touch
            CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
            if (iOSDeviceScreenSize.height == 480){
                // iPhone 3/4x
                storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_4" bundle:nil];

            }else if (iOSDeviceScreenSize.height == 568){
                // iPhone 5 etc
                storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_5" bundle:nil];
            }
        }
    }

    ASSERT(storyBoard);
    return storyBoard;
}

UIStoryboard* mainStoryBoard = [self getStoryboard];
    self.initialViewController = [mainStoryBoard instantiateInitialViewController];
    self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
    self.window.rootViewController = self.initialViewController;
    [self.window makeKeyAndVisible];
于 2013-01-24T14:24:12.833 回答