就像一个应用程序为 iPad 和 iPhone 使用不同的故事板一样,我希望我的应用程序为 iPhone 5 使用不同的故事板。由于 Info.plist 中没有选择 iPhone 5 的默认故事板的选项,我将如何以编程方式调用故事板?
我不想为这个应用程序使用自动布局,除非它绝对是最后的手段。我了解如何检测用户是否使用 iPhone 5 或具有相同屏幕尺寸的其他设备。我只需要知道如何在没有 plist 的情况下设置默认情节提要。
就像一个应用程序为 iPad 和 iPhone 使用不同的故事板一样,我希望我的应用程序为 iPhone 5 使用不同的故事板。由于 Info.plist 中没有选择 iPhone 5 的默认故事板的选项,我将如何以编程方式调用故事板?
我不想为这个应用程序使用自动布局,除非它绝对是最后的手段。我了解如何检测用户是否使用 iPhone 5 或具有相同屏幕尺寸的其他设备。我只需要知道如何在没有 plist 的情况下设置默认情节提要。
几周前我一直在寻找相同的答案,这是我的解决方案,希望对您有所帮助..
-(void)initializeStoryBoardBasedOnScreenSize {
if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
{ // The iOS device = iPhone or iPod Touch
CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
if (iOSDeviceScreenSize.height == 480)
{ // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35
UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone35" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
}
if (iOSDeviceScreenSize.height == 568)
{ // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone4" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
}
} else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)
{ // The iOS device = iPad
UISplitViewController *splitViewController = (UISplitViewController *)self.window.rootViewController;
UINavigationController *navigationController = [splitViewController.viewControllers lastObject];
splitViewController.delegate = (id)navigationController.topViewController;
}
}
在 AppDelegate ddiFinishLaunchingWithOptions: 方法下调用此方法并且也不要正确忘记故事板的名称
希望有帮助...
这对我有用 - 通过将故事板包装在一个函数中进行轻微改进
-(UIStoryboard*) getStoryboard {
UIStoryboard *storyBoard = nil;
if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad) {
storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPad" bundle:nil];
}else{
if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone){
// The iOS device = iPhone or iPod Touch
CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
if (iOSDeviceScreenSize.height == 480){
// iPhone 3/4x
storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_4" bundle:nil];
}else if (iOSDeviceScreenSize.height == 568){
// iPhone 5 etc
storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_5" bundle:nil];
}
}
}
ASSERT(storyBoard);
return storyBoard;
}
UIStoryboard* mainStoryBoard = [self getStoryboard];
self.initialViewController = [mainStoryBoard instantiateInitialViewController];
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
self.window.rootViewController = self.initialViewController;
[self.window makeKeyAndVisible];