7

我正在尝试在 java 中模拟 CPU 调度算法并使用多线程。我已经成功实现了 FCFS(先到先服务)和 SJF(最短工作优先)。但问题是当我开始想到 SRTF(最短剩余时间优先)时,它是 SJF 的一种抢先形式。我正在使用以下模型:

  • CPU 的一个线程,它有一个CLOCK变量,每个100ms. 我有一个boolean isAvailable;标志让进程在开始执行之前检查 CPU 是否可用。
  • Long Term Scheduler(LTS) 的线程,它将进程从进程列表推送到就绪队列。
  • Short Term Scheduler (STS) 的线程,它从 ReadyQueue 中获取一个进程并将其分配给 CPU。
  • 一旦一个进程被 STS 从 ReadyQueue 中删除以执行,该进程就会检查isAvailableCPU 的标志。如果true,它将标志设置为 false 并开始执行(为此我只是让线程休眠,(100 * burstTime) ms因为这只是一个模拟)。否则,该过程只是忙于等待: while(CPU.isAvailable != true);

我事先有进程列表以及它们的到达和突发时间。在我模拟非抢占式调度(FCFS 和 SJF)之前没关系。但是当我尝试使用 SRTF 时,我无法找到一种方法来抢占当前正在运行的进程线程。

对于 SRTF,我知道从 ReadyQueue 中选择下一个进程的方法。一旦我从队列中选择了一个进程,我可以尝试将isAvailable标志设置为false,但是我如何知道最初执行的是哪个线程?而且由于我没有使用太多同步黑白线程,因此我将有多个进程使用该CPU线程。它变得有点乱了。请帮忙。谢谢!

这是进程的代码:

enum State {ARRIVED, WAITING, READY, RUNNING, EXECUTED}
public class Process implements Runnable
{
    int pid;
    int arrTime;
int burstTime;
int priority;
long startTime;
long endTime;
State procState = null;

Process(int pid, int arrTime, int burstTime, int priority)
{
    this.pid = pid;
    this.arrTime = arrTime;
    this.burstTime = burstTime;
    this.priority = priority;
    this.procState = State.ARRIVED;
    this.startTime = 0;


    this.endTime = 0;    /* I also considered adding a timeElapsedUnderExecution
 attribute to the process. So I can check after every cycle if the CPU is still available
 and keep incrementing the time elapsed. Once the timeElapsed becomes same as burstTime, i
 stop the process. Or if after a cycle, the CPU is not available, i know from where to
 resume my Process. Is this the way to go ? */

    }

boolean isReady()
{
    if((this.arrTime <= CPU.CLOCK) && (this.procState == State.ARRIVED))
        return true;
    else return false;
}

@Override
public void run() {
    // TODO Auto-generated method stub
    if(this.procState == State.READY)
        this.procState = State.WAITING;

    while(!CPU.isAvailable());

    try 
    {
        this.procState = State.RUNNING;
        System.out.println("Process " + pid + " executing...");
        this.startTime = CPU.CLOCK;
        System.out.println("Process " + this.pid + ": Begins at " + this.startTime);
        Thread.sleep(this.burstTime * 100);
        this.endTime = CPU.CLOCK;
        System.out.println("Process " + this.pid + ": Ends at " + this.endTime);
        this.procState = State.EXECUTED;

    }
    catch (InterruptedException e) 
    {
        // TODO Auto-generated catch block
        System.out.println("Interrupted: " + pid);
        e.printStackTrace();
    }
    }
}

CPU的代码:

    import java.util.LinkedList;
    import java.util.Queue;

    public class CPU implements Runnable

{
    static Long CLOCK = new Long(0);
    static LinkedList<Process> ReadyQ = new LinkedList<Process>();
private static boolean isAvailable = true;
static boolean done = false;

public static boolean isAvailable() {
    return isAvailable;
}

public static void setAvailable(boolean isAvailable) {
    CPU.isAvailable = isAvailable;
}

static void incrementCLOCK()
{
    LTS.checkArrival();
    CPU.CLOCK++;
    try {
        Thread.sleep(100);
    } catch (InterruptedException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    System.out.println("Clock Tick: " + CPU.CLOCK);
}

@Override
public void run() {
    // TODO Auto-generated method stub
    System.out.println("CPU starts.!!!");
    while(CPU.done != true)
        synchronized(CPU.CLOCK)
        {
            incrementCLOCK();
            }
    }
}

LTS 的代码:

public class LTS implements Runnable 
{
    private static Process[] pList = null;
    private final int NUM;
    static Integer procStarted;
    static Integer procFinished;
    static boolean STSDone = false;


LTS(Process[] pList, int num)
{
    this.NUM = num;
    LTS.pList = pList;
}

static void checkArrival()
{
    if(pList == null) return;
    for(int i = 0; i < pList.length; i++)
        if(pList[i].isReady())
        {
            pList[i].procState = State.READY;
            System.out.println("Process " + pList[i].pid + " is now ready.");
            CPU.ReadyQ.add(pList[i]);
        }
}

@Override
public void run() {
    // TODO Auto-generated method stub
    System.out.println("Long Term Scheduler starts.!!!");
    while(LTS.STSDone != true)
    {
        try {
            Thread.sleep(100);
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
    System.out.println(LTS.STSDone);
    System.out.println("LTS ends.!!!");
        CPU.done = true;
    }
}
4

1 回答 1

0

问题 1 是您的共享状态不是线程安全的。即使像布尔值这样简单的东西也需要正确的线程原语来确保跨线程的可见性(又名“易失性”)。

于 2012-10-01T20:31:42.653 回答