因为您没有提供代码,所以我无法准确确定您想要做什么,但这里有一个传递数组并返回您应该能够推断的数组的示例。
编辑:只是为了好玩,将其更新为最多可用于 3 维数组。
Public Sub Test()
'Defines testArray as Variant 0 to 10
Dim testArray(0 To 1, 0 To 6) As Long
Dim returnArray() As Long
Dim i As Long
Debug.Print UBound(testArray, 2)
'Populates testArray with Longs
For i = 0 To UBound(testArray, 1)
For j = 0 To UBound(testArray, 2)
testArray(i, j) = (i + j) * 2
Next
Next
'Passes testArray and returns ParseArray
returnArray = addOne(testArray)
End Sub
Public Function addOne(arrValues() As Long) As Variant
Dim arrCopy() As Long
Dim dimensionNum As Long, ErrorCheck As Long
On Error Resume Next
For dimensionNum = 1 To 60000
ErrorCheck = LBound(arrValues, dimensionNum)
If Err.Number <> 0 Then
dimensionNum = dimensionNum - 1
Exit For
End If
Next
Dim i As Long, j As Long, k As Long
'Copies passed array to avoid updating passed array directly
arrCopy = arrValues
'Adds 1 to each element of the array.
If dimensionNum = 1 Then
For i = LBound(arrCopy) To UBound(arrCopy)
arrCopy(i) = arrCopy(i) + 1
Next
ElseIf dimensionNum = 2 Then
For i = LBound(arrCopy) To UBound(arrCopy)
For j = LBound(arrCopy, 2) To UBound(arrCopy, 2)
arrCopy(i, j) = arrCopy(i, j) + 1
Next
Next
ElseIf dimensionNum = 3 Then
For i = LBound(arrCopy) To UBound(arrCopy)
For j = LBound(arrCopy, 2) To UBound(arrCopy, 2)
For k = LBound(arrCopy, 3) To UBound(arrCopy, 3)
arrCopy(i, j, k) = arrCopy(i, j, k) + 1
Next
Next
Next
Else
MsgBox "Add function only works for three dimensions or fewer arrays"
End If
addOne = arrCopy
End Function