iphone - 如何将格式化的 nsstring 转换为 NSNumber 或删除格式？

Question

我有一个像“1.23,45”这样的字符串，（德国/法国风格或其他风格）。如何将格式删除为普通字符串或 nsnumber？我只知道从数字转换为字符串。:(谢谢。

Answer 1

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];  
    [formatter setNumberStyle:NSNumberFormatterCurrencyStyle];
    [formatter setCurrencySymbol:@""];  

    NSLocale *locale = [[NSLocale alloc] initWithLocaleIdentifier:@"en_US"];
    [formatter setLocale:locale];
    NSString *formattedOutput = [formatter stringFromNumber:[NSNumber numberWithFloat:[aPrice floatValue]]];
    [locale release];
    [formatter release];
    NSLog(@"%@", formattedOutput];

进一步将 formattedString 转换为数字

NSNumber myNumber = [formattedOutput intValue]; //replace intValue by floatValue to get decimal output

Answer 2

您可以使用 a将 a 转换NSString为a ，但您必须告诉它您为字符串使用的语言环境（在本例中为德语）：NSNumberNSNumberFormatter

// Create a number formatter that can convert from/to German currency:
NSNumberFormatter *formatter    = [[NSNumberFormatter alloc] init];
formatter.numberStyle           = NSNumberFormatterCurrencyStyle;
formatter.locale                = [[NSLocale alloc] initWithLocaleIdentifier:@"de_DE"];
[formatter setLenient:YES];

// Use the number formatter to create a NSNumber:
NSNumber *number                = [formatter numberFromString:@"1.23,45"];

// Return the number formatter to the current user's locale:
formatter.locale                = [NSLocale currentLocale];

// Finally, create a string from the NSNumber formatted in the user's locale:
NSString *formattedString       = [formatter stringFromNumber:number];

Answer 3

It sounds like you need to do two things:

1) break the string into an arrays of substrings based upon comma separation

NSString *startString = @"1.23,45";
NSArray *subStringArray= [colorStr componentsSeparatedByString:@","];

2) convert each substring to a number

NSNumberFormatter * formatter = [[NSNumberFormatter alloc] init];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
NSString *subString = [subStringArray objectAtIndex:0];
NSNumber *thisNumber = [formatter numberFromString:subString];
NSLog (@"thisNumber: %@", thisNumber);

Answer 4

  NSNumber * myNumber  = [NSNumber numberWithInt:[@"1.23,45" intValue]];

或者

  NSNumber * myNumber  = [NSNumber numberWithFloat:[@"1.23,45" floatValue]];

注意：最好从字符串中修剪逗号（，）符号

您可以使用以下方法

+ (NSNumber *)numberWithChar:(char)value;
+ (NSNumber *)numberWithUnsignedChar:(unsigned char)value;
+ (NSNumber *)numberWithShort:(short)value;
+ (NSNumber *)numberWithUnsignedShort:(unsigned short)value;
+ (NSNumber *)numberWithInt:(int)value;
+ (NSNumber *)numberWithUnsignedInt:(unsigned int)value;
+ (NSNumber *)numberWithLong:(long)value;
+ (NSNumber *)numberWithUnsignedLong:(unsigned long)value;
+ (NSNumber *)numberWithLongLong:(long long)value;
+ (NSNumber *)numberWithUnsignedLongLong:(unsigned long long)value;
+ (NSNumber *)numberWithFloat:(float)value;
+ (NSNumber *)numberWithDouble:(double)value;
+ (NSNumber *)numberWithBool:(BOOL)value;
+ (NSNumber *)numberWithInteger:(NSInteger)value NS_AVAILABLE(10_5, 2_0);
+ (NSNumber *)numberWithUnsignedInteger:(NSUInteger)value NS_AVAILABLE(10_5, 2_0);