在我的 java 代码中, threadB 创建nb *threadA 并等待myobj的值等于nb。 myobj最初等于 0 并且每个 threadA 递增它,当它等于nb时,最后一个 threadA 通知 ThreadB。
运行程序时,不会通知 threadB 并且不会继续运行。谁能告诉我这段代码的问题在哪里?
public class Myclass {
static Long myobj = new Long(0);
static int nb = 1;
public static void main(String[] args) {
ThreadA[] threadA = new ThreadA[nb];
ThreadB threadB = new ThreadB(threadA);
}
}
public class ThreadA extends Thread {
public ThreadA() {
this.start();
}
public void run() {
// do lot of computation
Myclass.myobj = Myclass.myobj + 1;
if (Myclass.myobj.intValue() == Myclass.myobj.nb) {
synchronized (Myclass.myobj) {
Myclass.myobj.notify();
}
}
}
}
public class ThreadB extends Thread {
ThreadA[] threadA;
public ThreadB(ThreadA[] threadA) {
this.threadA = threadA;
this.start();
}
public void run() {
for (int i = 0; i < threadA.length; i++) {
threadA[i] = new ThreadA();
}
synchronized (Myclass.myobj) {
while (Myclass.myobj.intValue() != Myclass.myobj.nb) {
Myclass.myobj.wait();
}
}
}
}