那是我的 mat_likes 表:
mat_id| yes| no
1 | 1 | 0
1 | 1 | 0
1 | 1 | 0
2 | 1 | 0
3 | 1 | 0
4 | 1 | 0
4 | 1 | 0
我怎样才能选择mat_id那些材料最多的yes = 1。Е减去结果的示例:
mat_id = 1, 因为有总yes = 3mat_id = 4, 因为有总yes = 2mat_id = 3, 因为有总yes = 1mat_id = 2, 因为有总yes = 1