mysql - 查找具有相同票证的不同条目之间的天数差异

Question

我有下表：

ticket    arrivaltime        resolution time    status

t1        '2012-09-03'        null               new
t2        '2012-09-04'        null               new
t1        (can be anything)   '2012-09-14'       verified    
t1        (can be anything)   '2012-09-16'       verified
t2        (can be anything)   '2012-09-06'       verified

例如，现在我想找到 t1 的天数差异：

Age(t1)=(resolution time of last entry) - (arrival time of first entry)

同样，我会为 t2 找到它。

我怎样才能找到这个？

Answer 1

您可以执行以下操作：

SELECT TICKET, DATE_DIFF(MAX(RESOLUTION_TIME) - MIN(ARRIVAL_TIME)) AS DIFF FROM TABLE GROUP BY TICKET

Answer 2

有关语法，请参阅以下链接

MySQL中的日期差异来计算年龄

SELECT TICKET, DATE_DIFF(MAX(RESOLUTION_TIME),MIN(ARRIVAL_TIME)) From TABLE