我有两张桌子:
+-----------+ +------------------------------------+--------------+
+ persons | | photos |
+-----------| +---------------------------------------------------+
+ id | name + | id | person_id | path | title |
+-----------+ +---------------------------------------------------+
+ 1 | Tom + | 1 | 2 | ~fred/me.png | Yo, it's Me! |
+ 2 | Fred + | 2 | 2 | ~fred/my_wife.png | I'm Susan |
+ 3 | Jack + | 3 | 1 | ~tom/my_dog.jpg | a woof |
+-----------+ +---------------------------------------------------+
在这种关系中:
Person hasMany Photo <-> Photo belongsTo Person
我想列出所有带有照片的人(即使有人没有,比如杰克),并按照片的标题排序。
我应该为此编写什么 SQL 查询(MySQL)?我可以在一对多关系中使用联接吗?
PS:作为一个信息,我希望能够用记录构造一个这样的数组:
$persons = Array(
[0] => Array(
[id] => 1,
[name] => 'Tom',
[Photo] => Array(
[0] => Array(
[id] => 3,
[person_id] => 1,
[path] => '~tom/my_dog.jpg',
[title] => 'a woof' // 1st
)
)
),
[1] => Array(
[id] => 2,
[name] => 'Fred',
[Photo] => Array(
[0] => Array(
[id] => 2,
[person_id] => 2,
[path] => '~fred/my_wife.png',
[title] => "I'm Susan" // 2nd
),
[0] => Array(
[id] => 1,
[person_id] => 2,
[path] => '~fred/me.png',
[title] => "Yo, it's Me!" // 3rd
)
)
),
[2] => Array(
[id] => 3,
[name] => 'Jack',
[Photo] => Array()
)
)
非常感谢!