我目前正在做一个项目,我正在阅读命令,我需要避免空白行出现空格。到目前为止,我做得很好,但由于某种原因,我似乎无法弄清楚如何让它发挥作用。我以为if(opcode == "\t" || opcode == " ")continue;
会照顾好,但没有。如果有人可以请看一下并帮助我,那就太好了。
这是我正在阅读的命令的一个小示例。它们采用 [label] 操作码 [arg1][,arg2] 格式。
#Sample Input
LA 1,1
LA 2,2
\t <<<<<<<Here just to show that it's a blank line with only a tab
TOP NOP
这是我的代码:
int counter = 0;
int i = 0;
int j = 0;
int p = 0;
while (getline(myFile, line, '\n'))
{
if (line.length() == 0)
{
continue;
}
if (line[0] == '#')
{
continue;
}
// If the first letter isn't a tab or space then it's a label
if (line[0] != '\t' && line[0] != ' ')
{
string delimeters = "\t ";
int current;
int next = -1;
current = next + 1;
next = line.find_first_of( delimeters, current);
label = line.substr( current, next - current );
Symtablelab[i] = label;
Symtablepos[i] = counter;
if(next>0)
{
current = next + 1;
next = line.find_first_of(delimeters, current);
opcode = line.substr(current, next - current);
if (opcode != "WORDS" && opcode != "INT")
{
counter += 3;
}
if (opcode == "INT")
{
counter++;
}
if (next > 0)
{
delimeters = ", \n\t";
current = next + 1;
next = line.find_first_of(delimeters, current);
arg1 = line.substr(current, next-current);
if (opcode == "WORDS")
{
counter += atoi(arg1.c_str());
}
}
if (next > 0)
{
delimeters ="\n";
current = next +1;
next = line.find_first_of(delimeters,current);
arg2 = line.substr(current, next-current);
}
}
i++;
}
// If the first character is a tab or space then there is no label and we just need to get a counter
if (line[0] == '\t' || line[0] == ' ')
{
string delimeters = "\t \n";
int current;
int next = -1;
current = next + 1;
next = line.find_first_of( delimeters, current);
label = line.substr( current, next - current );
if(next>=0)
{
current = next + 1;
next = line.find_first_of(delimeters, current);
opcode = line.substr(current, next - current);
if (opcode != "WORDS" && opcode != "INT")
{
counter += 3;
}
if (opcode == "INT")
{
counter++;
}
if (next > 0)
{
delimeters = ", \n\t";
current = next + 1;
next = line.find_first_of(delimeters, current);
arg1 = line.substr(current, next-current);
if (opcode == "WORDS")
{
counter += atoi(arg1.c_str());
}
}
if (next > 0)
{
delimeters ="\n\t ";
current = next +1;
next = line.find_first_of(delimeters,current);
arg2 = line.substr(current, next-current);
}
}
}
}