6

我有一系列ggplots 我想按如下所示排列并插入到通过knitr. 而不是一个非常小的肖像人物,我想把它旋转成横向,这样它就可以尽可能地填满页面。有任何想法吗?

library(ggplot2)
library(grid)
df <- data.frame(x = 1:100, y =rnorm(100))
plota <- ggplot(df, aes(x, y)) + geom_point(size = 4)


pushViewport(viewport(layout = grid.layout(3, 5)))
vplayout <- function(x, y) viewport(layout.pos.row = x, layout.pos.col = y) 
        print(plota, vp = vplayout(1:2, 1:2)) 
        print(plota, vp = vplayout(1, 3)) 
        print(plota, vp = vplayout(1, 4))
        print(plota, vp = vplayout(1, 5))
        print(plota, vp = vplayout(2, 3)) 
        print(plota, vp = vplayout(2, 4))
        print(plota, vp = vplayout(2, 5))
        print(plota, vp = vplayout(3, 1))
        print(plota, vp = vplayout(3, 2))
        print(plota, vp = vplayout(3, 3))
        print(plota, vp = vplayout(3, 4))
        print(plota, vp = vplayout(3, 5))
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1 回答 1

6

在 LaTeX 中旋转图形很容易;您可以使用选项angle=90,如http://yihui.name/knitr/options中所述;请参阅下面的完整示例:

\documentclass{article}
\begin{document}

<<out.extra='angle=90'>>=
library(ggplot2)
library(grid)
df <- data.frame(x = 1:100, y =rnorm(100))
plota <- ggplot(df, aes(x, y)) + geom_point(size = 4)

pushViewport(viewport(layout = grid.layout(3, 5)))
vplayout <- function(x, y) viewport(layout.pos.row = x, layout.pos.col = y) 
        print(plota, vp = vplayout(1:2, 1:2)) 
        print(plota, vp = vplayout(1, 3)) 
        print(plota, vp = vplayout(1, 4))
        print(plota, vp = vplayout(1, 5))
        print(plota, vp = vplayout(2, 3)) 
        print(plota, vp = vplayout(2, 4))
        print(plota, vp = vplayout(2, 5))
        print(plota, vp = vplayout(3, 1))
        print(plota, vp = vplayout(3, 2))
        print(plota, vp = vplayout(3, 3))
        print(plota, vp = vplayout(3, 4))
        print(plota, vp = vplayout(3, 5))
@

\end{document}
于 2012-09-16T00:52:15.553 回答