This question shows research effort; it is useful and clear
-2
This question does not show any research effort; it is unclear or not useful
Bookmark this question.
Show activity on this post.
我有一个 SQL 查询,它返回重复字段以跟踪操作。
SELECT contratosfianzas.adquisicion_contrato, count(*) as no_ope
From contratosfianzas
GROUP BY contratosfianzas.adquisicion_contrato
HAVING count(*) > 1