objective-c - 如何在目标c中取两个字符串的联合和交互？

Question

我有一个要求，比如在目标 c 的字符级别上使用 UNION 和 INTERSECTION。

“字符串A”，“字符串B”

上述字符串的（UNION）情况下的结果：“StringAB” 上述字符串的（交集）情况下的结果：“String”

任何帮助，将不胜感激。

Answer 1

在stackoverflow成员的帮助下，我终于解决了这些问题

路口：

NSMutableSet *set1 = [NSMutableSet setWithArray: array1];
NSSet *set2 = [NSSet setWithArray: array2];
[set1 intersectSet: set2];
NSArray *resultArray = [set1 allObjects];

UNION：连接两个字符串并从该字符串中删除重复的字符，最后你会得到 UNION :)

SString *input = @"addbcddaa";
NSMutableSet *seenCharacters = [NSMutableSet set];
NSMutableString *result = [NSMutableString string];
[input enumerateSubstringsInRange:NSMakeRange(0, input.length) options:NSStringEnumerationByComposedCharacterSequences usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
    if (![seenCharacters containsObject:substring]) {
        [seenCharacters addObject:substring];
        [result appendString:substring];
    }
}];
NSLog(@"String with duplicate characters removed: %@", result);
NSLog(@"Sorted characters in input: %@", [seenCharacters.allObjects sortedArrayUsingSelector:@selector(compare:)]);

谢谢！