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在这里，我在临时字符串中得到 xml 响应。我需要从该 xml 响应中获取一个标记值。

-(void) httpDataDidFinishLoadingWithData:(NSData *)theData
{
    m_activityLoaded=NO;
    temp=[[NSString alloc] initWithData:[dataLoader httpData]  encoding:NSUTF8StringEncoding];
    NSLog(@"TEMP IS TEMP %@", temp);
    parser=[[NSXMLParser alloc] initWithContentsOfURL:[NSURL URLWithString:temp]];
    [parser setShouldProcessNamespaces:NO];
    [parser setShouldReportNamespacePrefixes:NO];
    [parser setShouldResolveExternalEntities:NO];
    parser.delegate=self;
    [parser parse];
}

问题是 DidStartElement 在上述解析器分配后甚至没有调用并准备解析。

- (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName
  namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qualifiedName
attributes:(NSDictionary *)attributeDict
{
    if(![elementName isEqual:@"Result"])
        return;
    woeid = [attributeDict objectForKey:@"woeid"];
    NSLog(@"woeid   %@", woeid);
}

我的 XML 响应是

<?xml version="1.0" encoding="UTF-8"?>
<Body><woied></woied></Body>

请帮我摆脱这些家伙。提前致谢

4

2 回答 2

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? [[NSXMLParser alloc] initWithContentsOfURL:[NSURL URLWithString:temp]]; ?

也许您应该使用 [[NSXMLParser alloc] initWithData:theData]; 创建解析器

于 2012-09-10T07:24:50.270 回答
0

你可以试试这个：

-(void) httpDataDidFinishLoadingWithData:(NSData *)theData
{
    m_activityLoaded=NO;
    temp=[[NSString alloc] initWithData:[dataLoader httpData]  encoding:NSUTF8StringEncoding];
    NSLog(@"TEMP IS TEMP %@", temp);
    parser=[[NSXMLParser alloc] initWithData:[temp dataUsingEncoding: NSUTF8StringEncoding];
    [parser setShouldProcessNamespaces:NO];
    [parser setShouldReportNamespacePrefixes:NO];
    [parser setShouldResolveExternalEntities:NO];
    parser.delegate=self;
    [parser parse];
}

我认为这可能可行。您将错误的数据传递给解析器。

于 2012-09-10T07:34:55.857 回答