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这里只是一个简单的问题。如何获得这种 xml 的返回值

 Art C. Cauyao<$@FBID@$>501912568<$@ENDFBID@$>Tessa Rose 
Brainard<$@FBID@$>510831686<$@ENDFBID@$>
Dan Gangan<$@FBID@$>513545777<$@ENDFBID@$>
C Jhec DawAko<$@FBID@$>523059320<$@ENDFBID@$>Jeremy

请查看我正在获取 Facebook 名称和 Facebook ID 有什么办法吗？

编辑

我发现它不是一个 xml 而是一个 JSON（对不起）现在我的问题真的是如何合并该返回值？

编辑第二 先生这是我在做什么通过这个解析它

static final String URL_FBFRIEND ="Some URL"+ "getFBFriends.php";

现在使用它，我现在可以使用我的输入值解析一些数据。这是代码

        XMLparser parser2 = new XMLparser(); 
    parser2.getXmlFromUrl(URL_FBFRIEND); 

      //HTTP POST
      String url_Getmembermob= URL_FBFRIEND ;
      String xml_getMembermob=null;
      try {
      HttpClient httpclient = new DefaultHttpClient();
      HttpPost httppost = new HttpPost(url_Getmembermob);

      List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(4); 
      nameValuePairs.add(new BasicNameValuePair("...", "...."));
      nameValuePairs.add(new BasicNameValuePair("fbID", modGen.facebookID ));
      nameValuePairs.add(new BasicNameValuePair("accToken", modGen.tokenID));
      nameValuePairs.add(new BasicNameValuePair("reqType", "0"));

      Log.i("nameValuePairs", "nameValuePairs=" + nameValuePairs);

        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse httpResponse = httpclient.execute(httppost);

        HttpEntity httpEntity = httpResponse.getEntity();

        xml_getMembermob = EntityUtils.toString(httpEntity);

        Log.i("xml-return",""+ xml_getMembermob);

    } catch (UnsupportedEncodingException e) {
        // TODO Auto-generated catch block
        e.printStackTrace(); 
    }catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

看到我正在记录返回的 xml Log.i("xml-return",""+ xml_getMembermob); 这就是输出

先生，我改变了你的代码` public static List parseUserList(String userData) { List ret = new ArrayList();

    int index = 0;
    while (index < userData.length())
    {
        int startFbTag = userData.indexOf(FB_NAME, index);
        if (index == -1)
        {

            return ret;
        }
        String name = userData.substring(index, startFbTag - index);
        startFbTag += FB_NAME.length(); // Start of the actual data
        int endFbTag = userData.indexOf(FB_ID, startFbTag);
        if (endFbTag == -1)
        {
            throw new IllegalArgumentException("Unterminated start tag");
        }

        fbTagValue = userData.substring(startFbTag, endFbTag - startFbTag);
        Log.i("UserName",fbTagValue);
        //fbId = Long.parseLong(fbTagValue);
        //ret.add(new User(name, fbId));
        index = endFbTag + FB_ID.length();
    }
    return ret;
}

我在这里遇到错误 ** fbTagValue = userData.substring(startFbTag, endFbTag - startFbTag);** 似乎是什么问题

4

1 回答 1

0

这是非常可怕的格式。它不是 XML。这不是 JSON。假设您已经有了某种User类，并且所有数据都在一个 中String，您可以编写如下内容（完全未经测试）：

private static final String FB_START = "<$@FBID@$>";
private static final String FB_END = "<$@ENDFBID@$>";

public static List<User> parseUserList(String userData)
{
    List<User> ret = new ArrayList<User>();

    int index = 0;
    while (index < userData.length())
    {
        int startFbTag = userData.indexOf(FB_START, index);
        if (index == -1)
        {
            // No tags left. You should check whether you've actually got
            // some data left, and potentially throw an exception. It's not
            // clear what your data format does here.
            return ret;
        }
        String name = userData.substring(index, startFbTag - index);
        startFbTag += FB_START.length(); // Start of the actual data
        int endFbTag = userData.indexOf(FB_END, startFbTag);
        if (endFbTag == -1)
        {
            throw new IllegalArgumentException("Unterminated start tag");
        }

        String fbTagValue = userData.substring(startFbTag, endFbTag - startFbTag);
        long fbId = Long.parseLong(fbTagValue);
        ret.add(new User(name, fbId));
        index = endFbTag + FB_END.length();
    }
    return ret;
}
于 2012-09-08T08:26:32.193 回答