0

情况：

我有一个Service（也尝试过使用一个Activity）在每次按钮单击时发送 SMS 消息。我 99.9% 确定该方法sendSMS(...)只被调用一次。Toasts在BroadcastReceiver屏幕上的任何地方从几秒钟到几乎是挑衅地创建，直到应用程序被强制停止。"SMS Sent"卡在屏幕上一段时间，短信发送成功。你可以看到Toast一点点淡入和淡出。

难道我做错了什么？

奖金：

为什么BroadcastReceiverwith "SMS delivered"status 没有得到任何响应？

这是我很久以前从教程中获取的非常通用的代码：

    @Override
public void onStart(Intent intent, int startId) {
    super.onStart(intent, startId);
    sendSMS("5555555","hello world");
}

@Override
public int onStartCommand(Intent intent, int flags, int startId) {
    super.onStartCommand(intent, flags, startId);
    sendSMS("5555555","hello world");
    return Service.START_STICKY;
}

  // ---sends an SMS message to another device---
private void sendSMS(final String phoneNumber, final String message) {
    String SENT = "SMS_SENT";
    String DELIVERED = "SMS_DELIVERED";

    PendingIntent sentPI = PendingIntent.getBroadcast(this.getApplicationContext(), 0, new Intent(
            SENT), 0);

    PendingIntent deliveredPI = PendingIntent.getBroadcast(this.getApplicationContext(), 0,
            new Intent(DELIVERED), 0);

    // ---when the SMS has been sent---
    registerReceiver(new BroadcastReceiver() {
        @Override
        public void onReceive(Context context, Intent intent) {
                switch (getResultCode()) {
                case Activity.RESULT_OK:
                    Toast.makeText(context, "SMS sent",
                            Toast.LENGTH_SHORT).show();
                    break;
                case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                    Toast.makeText(context, "SMS error: Generic failure",
                            Toast.LENGTH_SHORT).show();
                    break;
                case SmsManager.RESULT_ERROR_NO_SERVICE:
                    Toast.makeText(context, "SMS error: No service",
                            Toast.LENGTH_SHORT).show();
                    break;
                case SmsManager.RESULT_ERROR_NULL_PDU:
                    Toast.makeText(context, "SMS error: Null PDU",
                            Toast.LENGTH_SHORT).show();
                    break;
                case SmsManager.RESULT_ERROR_RADIO_OFF:
                    Toast.makeText(context, "SMS error: Radio off",
                            Toast.LENGTH_SHORT).show();
                    break;
            }
        }
    }, new IntentFilter(SENT));

    // ---when the SMS has been delivered---
    registerReceiver(new BroadcastReceiver() {
        @Override
        public void onReceive(Context context, Intent intent) {
            switch (getResultCode()) {
            case Activity.RESULT_OK:
                Toast.makeText(context, "SMS delivered",
                        Toast.LENGTH_SHORT).show();
                break;
            case Activity.RESULT_CANCELED:
                Toast.makeText(context, "SMS not delivered",
                        Toast.LENGTH_SHORT).show();
                break;
            }
        }
    }, new IntentFilter(DELIVERED));

    SmsManager sms = SmsManager.getDefault();
    sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);
}

/编辑：修复了问题，您可以在此问题的评论中阅读

4

3 回答 3

0

打sendSMS()了两次电话，罪魁祸首是onStart()我的服务不推荐使用的方法

@Override
public void onStart(Intent intent, int startId) {
    //super.onStart(intent, startId);
    sendSMS("5555555","hello world");
}

@Override
public int onStartCommand(Intent intent, int flags, int startId) {
    //super.onStartCommand(intent, flags, startId);
    sendSMS("5555555","hello world");
    return Service.START_STICKY;
}

这个答案帮助我保留了两种方法

于 2012-09-07T09:31:12.323 回答
0

您可以使用这种方法以低于Toast.LENGTH_SHORT.

于 2012-09-07T09:01:11.563 回答
-3

用这个来显示

Toast.makeText(context,message, 1000).show();

其中 1000 是以毫秒为单位的持续时间

于 2012-09-07T09:01:35.803 回答