sql - ORACLE SQL 获取从 2 个选择语句中检索到的两个值的差异

Question

我们有 2 个非常简单的 SELECT 语句：

SELECT value from table where date between DATE1 and DATE2
SELECT value from table where date between DATE3 and DATE4

我们需要一种编写单个 SQL 语句的方法，该语句将获取从这两个 SQL 语句返回的“值”的差异。

我们尝试了以下方法，但没有成功：

SELECT value from table where date between DATE1 and DATE2
minus 
SELECT value from table where date between DATE3 and DATE4

任何建议都受到高度赞赏。

Answer 1

未经测试但应该可以工作：

SELECT
    (SELECT value from table where date between DATE1 and DATE2) - 
    (SELECT value from table where date between DATE3 and DATE4)
FROM dual;

假设您SELECT value保证返回单个值

Answer 2

SELECT value FROM TBL WHERE date BETWEEN DATE1 and DATE2 
AND value NOT IN (SELECT value FROM TBL WHERE date BETWEEN DATE3 AND DATE4)

Answer 3

如果您认为您的内部查询可以给出多个值，请在下面使用

SELECT
    (SELECT sum(value) from table where date between DATE1 and DATE2) - 
    (SELECT sum(value) from table where date between DATE3 and DATE4) as answer
FROM dual;

Answer 4

请试试这个：

SET SERVEROUTPUT ON
DECLARE
V_FIRST NUMBER := 0;
V_SECOND NUMBER := 0;
BEGIN
  SELECT value into V_FIRST from table where rownum=1 and date between DATE1 and DATE2;
  SELECT value into V_SECOND from table where rownum=1 and date between DATE3 and DATE4;

  DBMS_OUTPUT.PUT_LINE (V_FIRST-V_SECOND); 
END;

Answer 5

(
SELECT value from table where date between DATE1 and DATE2
 minus 
SELECT value from table where date between DATE3 and DATE4
)
union all
(
SELECT value from table where date between DATE3 and DATE4
 minus 
SELECT value from table where date between DATE1 and DATE2
)

Answer 6

以下陈述应适用于您的情况

(
SELECT value from table where date between DATE3 and DATE4
 minus 
SELECT value from table where date between DATE1 and DATE2
)
union
(
SELECT value from table where date between DATE1 and DATE2
 minus 
SELECT value from table where date between DATE3 and DATE4
)