我正在尝试使用Spring Integration with Twitter在我的 Windows XP 机器上使用独立程序向我的 Twitter 帐户发布消息。但我收到以下错误 -
WARNING: POST request for "https://api.twitter.com/1/statuses/update.json" resulted in 401 (Unauthorized); invoking error handler
Exception in thread "main" org.springframework.integration.MessageHandlingException: error occurred in message handler [org.springframework.integration.twitter.outbound.StatusUpdatingMessageHandler#0]
at org.springframework.integration.handler.AbstractMessageHandler.handleMessage(AbstractMessageHandler.java:79)
at org.springframework.integration.dispatcher.UnicastingDispatcher.doDispatch(UnicastingDispatcher.java:115)
at org.springframework.integration.dispatcher.UnicastingDispatcher.dispatch(UnicastingDispatcher.java:102)
at org.springframework.integration.channel.AbstractSubscribableChannel.doSend(AbstractSubscribableChannel.java:77)
at org.springframework.integration.channel.AbstractMessageChannel.send(AbstractMessageChannel.java:157)
at org.springframework.integration.channel.AbstractMessageChannel.send(AbstractMessageChannel.java:128)
at com.skilledmonster.spring.integration.twitter.TwitterOutbound.main(TwitterOutbound.java:20)
Caused by: org.springframework.social.RevokedAuthorizationException: The authorization has been revoked. Reason: Unknown
at org.springframework.social.twitter.api.impl.TwitterErrorHandler.handleClientErrors(TwitterErrorHandler.java:96)
at org.springframework.social.twitter.api.impl.TwitterErrorHandler.handleError(TwitterErrorHandler.java:58)
at org.springframework.web.client.RestTemplate.handleResponseError(RestTemplate.java:486)
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:443)
at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:415)
at org.springframework.web.client.RestTemplate.postForObject(RestTemplate.java:294)
at org.springframework.social.twitter.api.impl.TimelineTemplate.updateStatus(TimelineTemplate.java:236)
at org.springframework.social.twitter.api.impl.TimelineTemplate.updateStatus(TimelineTemplate.java:224)
at org.springframework.integration.twitter.outbound.StatusUpdatingMessageHandler.handleMessageInternal(StatusUpdatingMessageHandler.java:57)
at org.springframework.integration.handler.AbstractMessageHandler.handleMessage(AbstractMessageHandler.java:73)
... 6 more
这是我的代码 -
twitter-outbound.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:int="http://www.springframework.org/schema/integration"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:twitter="http://www.springframework.org/schema/integration/twitter"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/integration/twitter
http://www.springframework.org/schema/integration/twitter/spring-integration-twitter-2.1.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/integration
http://www.springframework.org/schema/integration/spring-integration-2.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan
base-package="com.apress.prospringintegration.social.twitter" />
<context:property-placeholder location="/twitter.properties" />
<int:channel id="twitterOutbound" />
<twitter:outbound-channel-adapter twitter-template="twitterTemplate" channel="twitterOutbound" />
<bean id="twitterTemplate"
class="org.springframework.social.twitter.api.impl.TwitterTemplate">
<constructor-arg value="${twitter.consumer-key}" />
<constructor-arg value="${twitter.consumer-secret}" />
<constructor-arg value="${twitter.access-token}" />
<constructor-arg value="${twitter.access-token-secret}" />
</bean>
</beans>
TwitterConfigurationTemplate.java
package com.skilledmonster.spring.integration.twitter;
import org.springframework.beans.factory.annotation.Value;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.social.twitter.api.impl.TwitterTemplate;
@Configuration
public class TwitterConfigurationTemplate {
@Value("${consumer-key}")
private String consumerKey;
@Value("${consumer-secret}")
private String consumerSecret;
@Value("${access-token}")
private String accessToken;
@Value("${access-token-secret}")
private String accessTokenSecret;
@Bean
public TwitterTemplate twitterTemplate() {
TwitterTemplate twitterOperations =
new TwitterTemplate(
consumerKey, consumerSecret, accessToken, accessTokenSecret);
return twitterOperations;
}
}
TwitterOutbound.java
package com.skilledmonster.spring.integration.twitter;
import java.util.Calendar;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.integration.Message;
import org.springframework.integration.MessageChannel;
import org.springframework.integration.message.GenericMessage;
public class TwitterOutbound {
public static void main(String[] args) {
ApplicationContext context = new ClassPathXmlApplicationContext("/twitter-outbound.xml", TwitterOutbound.class);
MessageChannel input = context.getBean("twitterOutbound", MessageChannel.class);
Message<String> message = new GenericMessage<String>("Testing new Twitter samples for #springintegration"+Calendar.getInstance().getTimeInMillis());
input.send(message);
}
}
twitter.properties
twitter.consumer-key=onj5cG1P9pe7n9qA8UI4EA
twitter.consumer-secret=2l7hqMafKYaTkVBW3YfuBfGdzCtmICOJwjOOCEeQ
twitter.access-token=792995125-dXmN1Pbw7sE4WttvAbX7ssxEn4lHaVd6uOX3IMxk
twitter.access-token-secret=a1EuvvONcphdqXpfJVjCdaIBDlMZSUL5pgimWuEtg
仅供参考 - 我确实使用 twitter4j 测试了我的 twitter 令牌和密钥，它似乎成功地将消息发布到 twitter。
这是我的 twitter4j 代码-
OAuthSetup.java
package com.skilledmonster.spring.integration.twitter;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Calendar;
import twitter4j.Status;
import twitter4j.Twitter;
import twitter4j.TwitterException;
import twitter4j.TwitterFactory;
import twitter4j.auth.AccessToken;
import twitter4j.auth.RequestToken;
public class OAuthSetup {
/**
* @param args
*/
public static void main(String args[]) throws Exception {
// The factory instance is re-useable and thread safe.
Twitter twitter = new TwitterFactory().getInstance();
//insert the appropriate consumer key and consumer secret here
twitter.setOAuthConsumer("onj5cG1P9pe7n9qA8UI4EA",
"2l7hqMafKYaTkVBW3YfuBfGdzCtmICOJwjOOCEeQ");
RequestToken requestToken = twitter.getOAuthRequestToken();
AccessToken accessToken = null;
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
while (null == accessToken) {
System.out.println("Open the following URL and grant access to your account:");
System.out.println(requestToken.getAuthorizationURL());
System.out.print("Enter the PIN(if aviailable) or just hit enter.[PIN]:");
String pin = br.readLine();
try{
if(pin.length() > 0){
accessToken = twitter.getOAuthAccessToken(requestToken, pin);
}else{
accessToken = twitter.getOAuthAccessToken();
}
} catch (TwitterException te) {
if(401 == te.getStatusCode()){
System.out.println("Unable to get the access token.");
}else{
te.printStackTrace();
}
}
}
//persist to the accessToken for future reference.
System.out.println(twitter.verifyCredentials().getId());
System.out.println("token : " + accessToken.getToken());
System.out.println("tokenSecret : " + accessToken.getTokenSecret());
//storeAccessToken(twitter.verifyCredentials().getId() , accessToken);
Status status = twitter.updateStatus("Testing new Twitter samples for springintegration # "+Calendar.getInstance().getTimeInMillis());
System.out.println("Successfully updated the status to [" + status.getText() + "].");
System.exit(0);
}
}
谁能建议我这里出了什么问题？