1

我正在编写一个 php 应用程序来操作 XML 文件。我尝试了 Perl XML 序列化器/反序列化器来转换 XML->php obj->json 进行操作然后将 json 转换回 xml 以打印出来。

这是原始 XML 的示例

<module name="AssignId" active="true"  description="user description">
  <dict name="params">
    <entry key="Adds">
     ...
    </entry>
  </dict>
</module>

转换为 JSON 如下所示：

{"name":"AssignId","active":"true","description":"add draggable class to figure","dict":{"name":"params","entry":[{"key":"Adds" ...
}}

最终结果 XML 如下所示：

<name>AssignId</name>
    <active>true</active>
    <description>add draggable class to figure</description>
    <dict>
        <name>params</name>
        <entry>
            <XML_Serializer_Tag>
                <key>Adds</key>
                  ...
            </XML_Serializer_Tag>
        </entry>
    </dict>
</name>

这是我的 2 节课

class JSON_toXML {

    var     $jsonObj,
            $phpObj,
            $serializer;

    public function __construct($options, $file_path) {
        $this->serializer = new XML_Serializer($options);
        $serializedDoc = $this->serializer->serialize(json_decode($file_path));
        if ($serializedDoc === true) {
            $this->jsonObj = $this->serializer->getSerializedData();
        } else {
            $this->jsonObj = NULL;
        }
    }
    public function print_obj() {
        echo "<pre>";
        echo($this->jsonObj);
        echo "</pre>";
    }
}


class XML_toJSON {

        var     $phpObj,
                $jsonObj,
                $unserializer;

        public function __construct($options, $file_path) {

            $this->unserializer = &new XML_Unserializer($options);
            $unserializedDoc = $this->unserializer->unserialize($file_path, true);
            $this->phpObj = $this->unserializer->getUnserializedData();
            $this->jsonObj = json_encode($this->phpObj);
        }

        public function print_phpObj() {
            echo "<pre>";
            print_r($this->phpObj);
            echo "</pre>";
        }

        public function get_phpObj() {
            return $this->phpObj;
        }

        public function print_jsonObj() {
            echo $this->jsonObj;
        }

        public function get_jsonObj() {
            return $this->jsonObj;
        }

    }

我想知道如何保持最终结果 XML 与原始格式相同？也许有更好的方法来做到这一点？谢谢！！！

4

1 回答 1

2

您需要能够区分属性和元素，但您的格式不能传达该信息。您需要首先更改格式，可能类似于以下内容：

{
   "element": "module",
   "attribs": {
      "name":        "AssignId",
      "active":      "true",
      "description": "add draggable class to figure"
   },
   "children": [
      {
         "element": "dict",
         "attribs": {
            "name": "params"
         },
         "children:" [
            ...
         ]
      }
   ]
}
于 2012-08-30T22:14:37.737 回答