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有没有一种使用 EXPONENTIAL PRECISION 打印的方法？我需要用小数字填充一些数据并在之后进行比较......

我有这样的：

(0) - Mesured estimatedTime for multithread in block: 1.4917951E16 s
(1) - Mesured estimatedTime for multithread in block: 7.531891E15 s
(2) - Mesured estimatedTime for multithread in block: 2.9287E13 s
(3) - Mesured estimatedTime for multithread in block: 3.28478435E17 s
(4) - Mesured estimatedTime for multithread in block: 6.038E12 s

我想这样打印：

(0) - Mesured estimatedTime for original in block: 0000.15595175E15 s           
(1) - Mesured estimatedTime for original in block: 0007.335638E15 s             
(2) - Mesured estimatedTime for original in block: 0416.66E15 s                 
(3) - Mesured estimatedTime for original in block: 0000.0390156852E15 s         
(4) - Mesured estimatedTime for original in block: 6642.0E15 s

我知道你可以这样强制它：

// Force minimum number of digits to left and right of decimal point
formatter = new DecimalFormat("0.0E0");
s = formatter.format(-1234.567);         // -1.2E3

但不知道我怎么能把它强制到Expo-Precision :((((帮助!! :/

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1 回答 1

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您似乎想暗示 1e15 的精度。

for (double d : new double[]{1.4917951E16, 7.531891E15, 2.9287E13, 3.28478435E17, 6.038E12})
    System.out.printf("%11fE15%n", d/1e15);

印刷

  14.917951E15
   7.531891E15
   0.029287E15
 328.478435E15
   0.006038E15

如果范围更宽，您可以使用 DecimalFormat

DecimalFormat df = new DecimalFormat();
df.setMaximumFractionDigits(300);
df.setGroupingUsed(false);
for(double d = 1 ; d <= 1e30; d *= 1e5) {
    System.out.println(df.format(d/1e15)+"E15");
}

印刷

0.000000000000001E15
0.0000000001E15
0.00001E15
1E15
100000E15
10000000000E15
于 2012-08-30T15:03:49.417 回答