mysql - MySQL - 返回匹配查询数据的行数？

Question

我有一个查询如下：

SELECT 1 FROM shop_inventory a JOIN shop_items b ON b.id=a.iid AND b.szbid=3362169 AND b.cid=a.cid WHERE a.cid=1 GROUP BY a.bought

我需要对这些数据做的唯一事情就是计算返回的行数（我可以用mysqli -> num_rows;. 但是，我想知道是否有一种方法可以返回与查询匹配的行数，而无需跑num_rows？

例如，查询应该返回一行，一个结果，number_of_rows。

我希望这是有道理的！

Answer 1

select count(*) as `number_of_rows`
from (
    select 1
    from shop_inventory a
    join shop_items b on b.id = a.iid
        and b.szbid = 3362169
        and b.cid = a.cid
    where a.cid = 1
    group by a.bought
) a

在这种情况下，由于您没有使用任何聚合函数并且GROUP BY仅仅是为了消除重复，您还可以执行以下操作：

select count(distinct a.bought) as `number_of_rows`
from shop_inventory a
join shop_items b on b.id = a.iid
    and b.szbid = 3362169
    and b.cid = a.cid