iphone - 如何将当前日期保存到 sqlite 数据库

Question

我创建了一个 sqlite 数据库。'Orders' 是一个包含 idOrder(int)、dateOrder(varchar) 和 discount(float) 的表。在 Bill.h 中，我将 dateBill 设置为 NSDate，那么如何将当前 dateBill 保存到表“订单​​”中？

Answer 1

看起来这个主题也在这里讨论过。在 iPhone 应用程序中将日期持久化到 SQLite3

+ (NSDate *) dateWithSQLiteRepresentation: (NSString *) myString;
{
    NSAssert3(myString, @"%s: %d; %s; Invalid argument. myString == nil",  __FILE__, __LINE__, __PRETTY_FUNCTION__);

    return [[self sqlLiteDateFormatter] dateFromString: myString];
}

+ (NSDate *) dateWithSQLiteRepresentation: (NSString *) myString timeZone: (NSString *) myTimeZone;
{
    NSString * dateWithTimezone = nil;
    NSDate * result = nil;

    NSAssert3(myString, @"%s: %d; %s; Invalid argument. myString == nil",  __FILE__, __LINE__, __PRETTY_FUNCTION__);
    NSAssert3(myTimeZone, @"%s: %d; %s; Invalid argument. myTimeZone == nil",  __FILE__, __LINE__, __PRETTY_FUNCTION__);

    dateWithTimezone = [[NSString alloc] initWithFormat: @"%@ %@", myString, myTimeZone];
    result = [[self sqlLiteDateFormatterWithTimezone] dateFromString: dateWithTimezone];
    [dateWithTimezone release];

    return result;
}

+ (NSString *) sqlLiteDateFormat;
{
    return @"yyyy-MM-dd HH:mm:ss";    
}

+ (NSString *) sqlLiteDateFormatWithTimeZone;
{
    static NSString * result = nil;

    if (!result) {
        result = [[NSString alloc] initWithFormat: @"%@ zzz", [self sqlLiteDateFormat]];
    }

    return result;    
}

+ (NSDateFormatter *) sqlLiteDateFormatter;
{
    static NSDateFormatter * _result = nil;

    if (!_result) {
        _result = [[NSDateFormatter alloc] init];
        [_result setDateFormat: [self sqlLiteDateFormat]];
    }

    return _result;
}

+ (NSDateFormatter *) sqlLiteDateFormatterWithTimezone;
{
    static NSDateFormatter * _result = nil;

    if (!_result) {
        _result = [[NSDateFormatter alloc] init];
        [_result setDateFormat: [self sqlLiteDateFormatWithTimeZone]];
    }

    return _result;
}


- (NSString *) sqlLiteDateRepresentation;
{
    NSString * result = nil;

    result = [[NSDate sqlLiteDateFormatter] stringFromDate: self];

    return result;
}

- (NSTimeInterval) unixTime;
{
    NSTimeInterval result = [self timeIntervalSince1970];

    return result;
}

#define SECONDS_PER_DAY 86400
#define JULIAN_DAY_OF_ZERO_UNIX_TIME 2440587.5
- (NSTimeInterval) julianDay;
{
    return [self unixTime]/SECONDS_PER_DAY + JULIAN_DAY_OF_ZERO_UNIX_TIME;
}

+ (NSDate *) dateWithJulianDay: (NSTimeInterval) myTimeInterval
{
    NSDate * result = [[NSDate date] timeIntervalSince1970];

    return result;
}

Answer 2

列的数据类型是 INTEGER

对于保存日期：

sqlite_bind_double(compiledStatement,1, [yourdate TimeIntervalSince1970]);

对于检索日期：

NSDate *gotDate = [NSDate dateWithTimeIntervalSinceNow: sqlite3_column_double(compiledStatement, 1)];

希望能帮助到你

问候

库尔迪普