我有如下数据:
我想要的是计算 PONo、PartNo 和 TrinityID 字段中的值,并输出如下数据:
如何在 SQL 中进行此计数?
select
Job_number, Item_code,
case when RTRIM(PONo) = '' or PONo is null then 0 else 1 end +
case when RTRIM(PartNo) = '' or PartNo is null then 0 else 1 end +
case when RTRIM(TrinityID) = '' or TrinityID is null then 0 else 1 end
as [Count]
from YourTable
试试这个:
select Job_Number = t.Job_Number ,
Item_Code = t.Item_Code ,
"Count" = sum( case ltrim(rtrim(coalesce( PONo , '' ))) when '' then 0 else 1 end
+ case ltrim(rtrim(coalesce( PartNo , '' ))) when '' then 0 else 1 end
+ case ltrim(rtrim(coalesce( TrinityID , '' ))) when '' then 0 else 1 end
)
from dbo.my_table t
group by t.Job_Number , t.Item_Code
如果要排除所有测试字段为空或为空的数据,请添加having
子句:
having sum( case ltrim(rtrim(coalesce( PONo , '' ))) when '' then 0 else 1 end
+ case ltrim(rtrim(coalesce( PartNo , '' ))) when '' then 0 else 1 end
+ case ltrim(rtrim(coalesce( TrinityID , '' ))) when '' then 0 else 1 end
) > 0
简单的!