我有两个矩阵:A 和 B。
- 我该如何存储它们?
- 如何使用 Accelerate 框架计算矩阵 A 的逆矩阵?
- 如何找到 A*B 的乘积?
- 如何使用 Accelerate 框架转置矩阵 A?
谢谢你回答我的问题!
帮助文件
#import <Foundation/Foundation.h>
#include <Accelerate/Accelerate.h>
@interface Working_with_matrices : NSObject
-(int)invert_matrix:(int) N andWithMatrix:(double*) matrix;
@end
实施文件
#import "Working_with_matrices.h"
#include <Accelerate/Accelerate.h>
@implementation Working_with_matrices
-(int) matrix_invert:(int) N andWithMatrix:(double*)matrix
{
int error=0;
int *pivot = malloc(N*N*sizeof(int));
double *workspace = malloc(N*sizeof(double));
dgetrf_(&N, &N, matrix, &N, pivot, &error);
if (error != 0) {
NSLog(@"Error 1");
return error;
}
dgetri_(&N, matrix, &N, pivot, workspace, &N, &error);
if (error != 0) {
NSLog(@"Error 2");
return error;
}
free(pivot);
free(workspace);
return error;
}
从主函数调用我的代码
#import <Foundation/Foundation.h>
#import "Working_with_matrices.h"
int main(int argc, const char * argv[])
{
int N = 3;
double A[9];
Working_with_matrices* wm=[[Working_with_matrices alloc]init];
A[0] = 1; A[1] = 1; A[2] = 7;
A[3] = 1; A[4] = 2; A[5] = 1;
A[6] = 1; A[7] = 1; A[8] = 3;
[wm invert_matrix:N andWithMatrix:A];
// [ -1.25 -1.0 3.25 ]
// A^-1 = [ 0.5 1.0 -1.5 ]
// [ 0.25 0.0 -0.25 ]
for (int i=0; i<9; i++)
{
NSLog(@"%f", A[i]);
}
return 0;
}