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我将文件上传到远程服务器。编码：

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, ZDURL.$url);
    curl_setopt($ch, CURLOPT_USERPWD, ZDUSER."/token:".ZDAPIKEY);

    $params = array('file_name' => '@'.$temp_file);
    curl_setopt($ch, CURLOPT_HEADER, 0);
    curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type: text/plain"));
    curl_setopt($ch, CURLOPT_POSTFIELDS, $params);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

    curl_setopt($ch, CURLINFO_HEADER_OUT, 0);
    curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0);
    curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0);
    $result = curl_exec($ch);
    $error = curl_error($ch);
    curl_close($ch);

但是在上传文件的顶部会出现信息：

------------------------------cfbe90a606af
Content-Disposition: form-data; name="file_name"; filename="C:\Program Files\xampp\tmp\phpF576.tmp"
Content-Type: application/octet-stream

由于此添加文本，图像格式错误

4

1 回答 1

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听起来您要向其发送数据的 URL 只需要请求正文中的文件，而不是表单提交。实现这一目标的最佳方法是使用CURLOPT_INFILE. 试试这个代码：

尝试这个

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, ZDURL.$url);
curl_setopt($ch, CURLOPT_USERPWD, ZDUSER."/token:".ZDAPIKEY);

// You need to detect the correct content type for the file you are sending.
// Although based on the current problem you have, it looks like the server
// ignores this anyway
curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type: image/jpeg"));

// Send the raw file in the body with no other data
$fp = fopen($temp_file, 'r');
curl_setopt($ch, CURLOPT_INFILE, $fp);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLINFO_HEADER_OUT, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);

$result = curl_exec($ch);
$error = curl_error($ch);

curl_close($ch);
fclose($fp);
于 2012-08-14T10:01:22.367 回答