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我自己加入了一个查询，我的代码在 ase isql 上运行正常。但是，当我想在 access 2007 中使用它时，我收到以下错误“派生表表达式缺少相关名称。检查参考手册中的派生表语法”原始代码执行以下操作：

 select TT.name, TT.lastname, max(amount) as maxsalecurrentweek
 from sales
 inner join
 (select s1.id_employee, e.name, e.lastname, e.address, e.age, e.id_employee 
 from employee e
 join sales s1 on e.id_emplyoee = s1.id_employee
 where 
 some conditions here) as TT
 on sales.id_employee = TT.id_employee
 group by
 TT.name, TT.lastname

在原始代码中，我在内部查询中加入了更多表以及一些 where 条件。但是上面的代码应该说明我做了什么。

看起来我自己加入表格的方式是访问问题。有谁知道正确的语法是什么？或者，如果 access/JET/ACE 支持这种内部连接，它自己的方法？

这是原始代码：

select max(tort140.BEL_GRLAG_AP) as MaxPensjonGr, TT.IDE_KUNDE_PRSNR,
TT.DAT_KUNDE_FOEDT_NUM, TT.AvtaleID, TT.Orgnr, TT.Arbeidsgiver, 
TT.Sivilstatus, TT.Polisestatus, TT.Årslønn from tort140 

    inner join 

        (select distinct tort128.NUM_AVTALE_ID as AvtaleID,
         tort009.IDE_ARBGIV_NR as Orgnr,
         tort134.NVN_ARBGIV as Arbeidsgiver,
         tort127.DAT_KUNDE_FOEDT_NUM as DAT_KUNDE_FOEDT_NUM,
         tort127.IDE_KUNDE_PRSNR as IDE_KUNDE_PRSNR,
         tort001.STA_SIVILSTATUS as Sivilstatus,
         tort128.typ_status as Polisestatus, 
         tort128.rte_polisegrad as Polisegrad,
         tort140.BEL_LOENN_AAR as Årslønn,
         tort138.IDE_SEKV_TORT138"
         from tort140 left join (tort138 join (tort128 join (tort134 join (tort009 join (tort001 join tort127 
         on tort127.DAT_KUNDE_FOEDT_NUM=tort001.DAT_KUNDE_FOEDT_NUM and tort127.IDE_KUNDE_PRSNR=tort001.IDE_KUNDE_PRSNR)
         on tort127.DAT_KUNDE_FOEDT_NUM=tort009.DAT_KUNDE_FOEDT_NUM and tort127.IDE_KUNDE_PRSNR=tort009.IDE_KUNDE_PRSNR)
         on tort009.IDE_ARBGIV_NR=tort134.IDE_ARBGIV_NR)
         on tort128.IDE_SEKV_TORT127 = tort127.IDE_SEKV_TORT127)
         on tort128.IDE_SEKV_TORT128 = tort138.IDE_SEKV_TORT128)
         on tort140.IDE_SEKV_TORT138 = tort138.IDE_SEKV_TORT138)

         where tort128.NUM_AVTALE_ID = '102356' and tort128.DAT_GYLDIG_FOM <= 20120101
            and (tort128.DAT_GYLDIG_TOM >= 19520000 or tort128.DAT_GYLDIG_TOM is null
            and tort128.DAT_HISTORISK is null and tort128.TYP_STATUS= 'akt' and tort127.DAT_KUNDE_FOEDT_NUM >= 19650000
            and tort127.DAT_KUNDE_FOEDT_NUM <= 19550000 and tort127.DAT_TERMINERT is null and tort127.DAT_REGISTRERT<= 19550000
            and tort009.DAT_SLUTT is null and tort134.DAT_HISTORISK is null
            and tort138.DAT_AKSJON=(select max(p.DAT_AKSJON) from tort138 p where 1=1 and p.IDE_SEKV_TORT128=tort128.IDE_SEKV_TORT128)

          ) as TT

          on TT.IDE_SEKV_TORT138 = tort140.IDE_SEKV_TORT138

Group by TT.IDE_KUNDE_PRSNR, TT.DAT_KUNDE_FOEDT_NUM, TT.AvtaleID, TT.Orgnr,
TT.Arbeidsgiver, TT.Sivilstatus, TT.Polisestatus, TT.Årslønn from tort140

内部查询在 access 2007 上运行没有任何问题。编写内部联接时收到错误消息。你认为这个查询可以适合访问吗？我是否缺少一些刹车或其他东西？

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1 回答 1

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您必须在 MS Access 中添加加入类型，单独加入是行不通的。

from employee e
 INNER join sales s1 on e.id_emplyoee = s1.id_employee

根据评论进行编辑，上面的行取自已发布的 SQL，并适合如下所示：

select TT.name, TT.lastname, max(amount) as maxsalecurrentweek
 from sales
 inner join
 (select s1.id_employee, e.name, e.lastname, e.address, e.age, e.id_employee 
 from employee e
 INNER join sales s1 on e.id_emplyoee = s1.id_employee
 where 
 some conditions here) as TT
 on sales.id_employee = TT.id_employee
 group by
 TT.name, TT.lastname
于 2012-08-13T16:39:33.263 回答