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我需要将图像从 iphone 应用程序上传到 PHP 服务器，以便在服务器上对该图像进行一些处理，然后在服务器完成处理后，我想将结果图像返回给 iphone 应用程序。

我已经有上传代码，但我无法从 php 服务器获取结果图像并将其显示在 iphone 应用程序中

请帮忙

这些是这里的代码：

上传的objective-c代码：

NSString *urlString =[NSString stringWithFormat:@"http://192.168.1.3/TEST%20IPHONE/upload.php"] ;
    NSURL *nsurl =[NSURL URLWithString:urlString];  
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:nsurl cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];   
    [request setURL:nsurl];  
    [request setHTTPMethod:@"POST"];

    self.editingImageView.image = nil;
  NSString * filename =  @"cartoonize.png";

    NSMutableData *body = [NSMutableData data];


    NSString *boundary = [NSString stringWithString:@"---------------------------14737809831466499882746641449"];
    NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@", boundary];
    [request addValue:contentType forHTTPHeaderField:@"Content-Type"];

    // file
    NSData *imageData = UIImageJPEGRepresentation(self.EditingImage, 90);

    [body appendData:[[NSString stringWithFormat:@"--%@\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];


     [body appendData:[[NSString stringWithString:[NSString stringWithFormat:@"Content-Disposition: attachment; name=\"userfile\"; filename=\"%@\"\r\n",filename]] dataUsingEncoding:NSUTF8StringEncoding]];

    [body appendData:[[NSString stringWithString:@"Content-Type: application/octet-stream\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];
    [body appendData:[NSData dataWithData:imageData]];
    [body appendData:[[NSString stringWithString:@"\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];



    // close form
    [body appendData:[[NSString stringWithFormat:@"--%@--\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];

    // set request body
    [request setHTTPBody:body];




    //return and test

    NSURLConnection * connection = [[NSURLConnection alloc] 
                                    initWithRequest:request
                                    delegate:self startImmediately:NO];

    [connection scheduleInRunLoop:[NSRunLoop mainRunLoop] 
                          forMode:NSDefaultRunLoopMode];
    [connection start];

这里的PHP代码：

<?php
//echo $_FILES["userfile"]["size"];
$allowedExts = array("jpg", "jpeg", "gif", "png");
$extension = end(explode(".", $_FILES["userfile"]["name"]));


if ( ($_FILES["userfile"]["size"] < 200000)
&& in_array($extension, $allowedExts))
  {
  if ($_FILES["userfile"]["error"] > 0)
    {
    //echo "Return Code: " . $_FILES["userfile"]["error"] . "<br />";
    }
  else
    {



      move_uploaded_file($_FILES["userfile"]["tmp_name"],
      "upload/" . $_FILES["userfile"]["name"]);


// some processing on the image and result image will be saved on this path upload/test.jpg

$file = "upload/test.JPG" ; 
$imageData = utf8_encode(file_get_contents($file));

echo $imageData;

}






  }
else
  {
  echo "Invalid file";
  }





?>

我从 NSUrlConnection 委托方法中获取数据，所以结果在我的 Objective-C 代码中的 NSData 对象中，但是我无法从这个 NSData 对象中获取图像，你们觉得呢？

4

1 回答 1

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您是否实现了NSURLConnection允许您读取请求响应的委托方法？如果是这样，您应该使用 anNSMutableData来累积从服务器返回的数据（这可能会被拆分为多个委托调用），然后使用UIImage诸如imageWithData:在客户端上创建图像之类的方法。例如：

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response {
    self.receivedImageData = [NSMutableData dataWithCapacity:[response expectedContentLength]];
}

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data {
    [self.receivedImageData appendData:data];
}

- (void)connectionDidFinishLoading:(NSURLConnection *)connection {
    UIImage *finishedImage = [UIImage imageWithData:self.receivedImageData];
    self.receivedImageData = nil;
}
于 2012-08-09T17:44:18.767 回答