1

在我的 Iphone 应用程序中，我使用 AFNetworking 将一些数据发布到网络服务并取回一些数据......

这是我的例子，我总是得到“假”作为回应，我做错了什么？

NSURL *baseURL = [NSURL URLWithString:@"http://myPath/Iphone/method"];


    AFHTTPClient *httpClient = [[AFHTTPClient alloc] initWithBaseURL:baseURL];
    [httpClient defaultValueForHeader:@"Accept"];

    NSDictionary *params = [NSDictionary dictionaryWithObjectsAndKeys:
                            [udid copy], @"uuid",
                            nil];


    NSMutableURLRequest *request = [httpClient requestWithMethod:@"POST" path:@"http://myPath/Iphone/method" parameters:params];


    AFHTTPRequestOperation *operation = [[AFHTTPRequestOperation alloc] initWithRequest:request];


    [httpClient registerHTTPOperationClass:[AFXMLRequestOperation class]];


    [operation setCompletionBlockWithSuccess:^(AFHTTPRequestOperation *operation, id responseObject) {
        response = [operation responseString];
        NSLog(@"response: %@",response);
    } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
        NSLog(@"error: %@", [operation error]);
    }];


    [operation start];

编辑：我在 Url 中调用的方法返回一个字符串（没有字符串不是假的）

  [HttpPost]
        public bool checkIphone(string uuid)
        {
           IDictionary<string,object> check  = Request.Properties;

           uuid = check["uuid"].ToString();

           //do anything with the uuid

           if (1<0)
           {
               return true;
           }
           else
           {
               return false;
           }

        }

我用我的iphone调用这个方法，通常它应该返回xml或者？

4

2 回答 2

5

您正在使用一种复杂的方式来构建操作，但它会起作用。但它应该可以工作，你缺少的是分配 XMLparser。在AFXMLRequestOperation的文档中进行了说明。

 NSMutableURLRequest *request = [httpClient requestWithMethod:@"POST" path:@"http://myPath/Iphone/method" parameters:params];

AFXMLRequestOperation *operation = [[AFXMLRequestOperation alloc] initWithRequest:request];
operation.responseXMLParser = xmlParser; //Here you should assign an instance of NSXMLParser to handle you XML parsing.

[operation setCompletionBlockWithSuccess:^(AFHTTPRequestOperation *operation, id responseObject) {
    response = [operation responseString];
    NSLog(@"response: %@",response);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"error: %@", [operation error]);
}];

也不需要通过 NSURLRequest 来AFHTTPClient创建，您可以轻松地自己创建一个或使用AFHTTPClient来AFHTTPRequestOperation为您创建。

要使用 AFHTTPClient 只返回服务器返回的任何内容：

// Don't include the method here
NSURL *baseURL = [NSURL URLWithString:@"http://myPath/Iphone/"];

AFHTTPClient *httpClient = [[AFHTTPClient alloc] initWithBaseURL:baseURL];
[httpClient defaultValueForHeader:@"Accept"];

NSDictionary *params = [NSDictionary dictionaryWithObjectsAndKeys:
                        [udid copy], @"uuid",
                        nil];

[httpClient postPath:@"method" parameters:params success:^(AFHTTPRequestOperation *operation, id responseObject) {
    // reponseObject will hold the data returned by the server.

}failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"Error retrieving data: %@", error);
}];
于 2012-08-08T11:53:54.317 回答
-1

你这里有错字吗？[udid copy], @"uuid",

于 2012-08-08T20:59:09.413 回答