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目前我正在尝试重构一个多维数组，它是数据库查询的结果。目标是最终将数组编码为 JSON，如下所示，但是我编写的 php 函数不起作用（请参见最后的代码）：

desiredJSONoutput = {"TypeA":[
    {"1":[
        {"TypeB":[4,5]},
        {"TypeC":[7,8,4]}]},
    {"2":[
        {"TypeB":[2,3]},
        {"TypeC":[6]}]},
    {"4":[
        {"TypeB":[33,12]},
        {"TypeC":[908]}]}]}

数据库结构为：

fromType    fromID      toType      toID
-----------------------------------------------------
TypeA       1       TypeB       4
TypeA       1       TypeB       5
TypeA       1       TypeC       7
TypeA       1       TypeC       8
TypeA       1       TypeC       4
TypeA       2       TypeB       2
TypeA       2       TypeB       3
TypeA       2       TypeC       6
TypeA       2       TypeB       33
TypeA       2       TypeB       12
TypeA       2       TypeC       908

我当前的 sql 查询的结果是这个 php 数组：

Array
(
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '1'
        ['toType'] => 'TypeB'
        ['toID'] => '4'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '1'
        ['toType'] => 'TypeB'
        ['toID'] => '5'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '1'
        ['toType'] => 'TypeC'
        ['toID'] => '7'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '1'
        ['toType'] => 'TypeC'
        ['toID'] => '8'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '1'
        ['toType'] => 'TypeC'
        ['toID'] => '4'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '2'
        ['toType'] => 'TypeB'
        ['toID'] => '2'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '2'
        ['toType'] => 'TypeB'
        ['toID'] => '3'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '2'
        ['toType'] => 'TypeC'
        ['toID'] => '6'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '3'
        ['toType'] => 'TypeB'
        ['toID'] => '33'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '3'
        ['toType'] => 'TypeB'
        ['toID'] => '12'  
    )
    Array
    (
        ['fromType'] => 'TypeA'
        ['fromID'] => '3'
        ['toType'] => 'TypeC'
        ['toID'] => '908'  
    )
)

我认为在编码为 JSON 之前我需要的重组数组是：

Array
    (
        ['TypeA'] => Array
            (
                ['1'] => Array
                    (
                        ['TypeB'] => Array
                            (
                                [0] => 4
                                [1] => 5
                            )
                        ['TypeC'] => Array
                            (
                                [0] => 7
                                [1] => 8
                                [2] => 4
                            )
                    )
                ['2'] => Array
                    (
                        ['TypeB'] => Array
                            (
                                [0] => 2
                                [1] => 3
                            )
                        ['TypeC'] => Array
                            (
                                [0] => 6
                            )
                    )
                ['3'] => Array
                    (
                        ['TypeB'] => Array
                            (
                                [0] => 33
                                [1] => 12
                            )
                        ['TypeC'] => Array
                            (
                                [0] => 908
                            )
                    )
            )  
    )

我不确定为什么下面的 PHP 代码没有将返回的 php 数组重构为我想要的结构：

class Utilities {
    public function linksReEncode($rowsArray) {
        $result = array();

        foreach ($rowsArray as $row) {

            $fromtype = $row['fromtype'];
            $fromID = $row['fromID'];
            $toType = $row['toType'];
            $toID = $row['toID'];

            $arr = $result[$fromType][$fromID][$toType];

            array_push($arr, $toID);
        }
    }
}

根据进一步的研究和@Waygood 的第一个答案进行编辑，这是我现在正在使用并且正在工作的功能。我想知道是否有必要对现有密钥进行所有检查，这是否是实现这一目标的最经济的方法

public function linksReEncode($rows) {
        $result = array();

        foreach ($rows as $row) {

            $fromType = $row['fromType'];
            $fromID = $row['fromID'];
            $toType = $row['toType'];
            $toID = $row['toID'];

            if(!array_key_exists($fromType, $result))
                $result[$fromType] = array();

            if(!array_key_exists($fromID, $result[$fromType]))
                $result[$fromType][$fromID] = array();

            if(!array_key_exists($toType, $result[$fromType][$fromID]))
                $result[$fromType][$fromID][$toType] = array();

            array_push($result[$fromType][$fromID][$toType], $toID);

        }
        return $result;
    }
4

1 回答 1

1

您只是在每个循环中重新定义 $arr，而不是更改 $result

改变：

$arr = $result[$fromType][$fromID][$toType];
array_push($arr, $toID);

到：

$result[$fromType][$fromID][$toType][]=$toID;
于 2012-08-07T12:30:59.533 回答