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我正在尝试从每个文件中获取信息并使用它来创建一个新文件。每个文件都有一行，由一系列数字组成。我希望一个文件的每一行与另一个文件的每一行对齐，然后将一个文件的一行中的每个数字与另一个文件中另一行的同一位置的另一个数字相遇。文件“Volume.txt”的每一行都移动了一个点（因此代码 k = j+1）。

*操作完成后，我不断收到一个汉字重复很多次。那么我哪里做错了？非常感谢！*

这是代码：

e = open('C:/Users/MC/Desktop/EODP.txt', 'r')
v = open('C:/Users/MC/Desktop/Z/Volume.txt', 'r')
n = open('C:/Users/MC/Desktop/vovere.txt', 'w')

m = 0 #Used later for letting me know that the first line in the new file completed

for i in range(0, 3256):  # there are 3257 lines per the two files EOPD and Volume
    l = []                # create a list to put data in during operation
    er = e.readline()     #
    es = er.split(', ')   # create a list the data from that line of file
    vr = v.readline()     #
    vs = vr.split(', ')   # same
    for  j in range(len(es)):
        k = j + 1         #  file Volume is shifted one point ahead
        try:
            if float(vs[k]) == 0.0:
                vovere = 0.0             # vovere is the name of the output for each point
            elif vs[k] == '' or vs[k] == ' ':
                vovere = 0.0
            else:
                vovere = float(es[j])/float(vs[k])
        except ValueError:         #kept getting this error: some points weren't numbers
            vovere = 0.0       
        except IndexError:         # Each file didn't always exactly equal in line length
            vovere = 0.0
        la = l.append(float(vovere)) #Creates the list for each new line in new file
    ls = str(la)
    l1 = ls.replace('[', '')    # Taking away extra notations so the new file is a little 
    l2 = l1.replace(']', '')    # more clean and can be put into other programs 
    n.write(l2)
    if m == 0:                 # From here on out is just for me, not necessary**
        print("The first line is done!")
        m += 1
    else:
        pass

e.close()                      #** Except these of course
print(e.closed)
print("Yes, EOPD.txt is closed")
v.close()
print(v.closed) 
print("Yes, Volume.txt is closed")
n.close()
print(n.closed) 
print("Yes, vovere.txt is now ready for further manipulation!!")
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1 回答 1

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如果我正确理解了这个问题，这应该可以解决问题：

from itertools import zip_longest # If this was python 2.x import izip_longest instead

if __name__ == '__main__':
    input1_lines = []
    input2_lines = []

    # Read all the input from first file
    with open('./input1.txt', 'r') as input1:
        input1_lines = input1.readlines()

    # Read all the input from first file
    with open('./input2.txt', 'r') as input2:
        input2_lines = input2.readlines()

    # Go through all the lines
    output_lines = []
    for line_number_index in range(len(input1_lines)):
    # For each line in each input file make a list of items and remove line breaks
        line1_items = str(input1_lines[line_number_index]).replace('\n', '').split(', ')
        line2_items = str(input2_lines[line_number_index]).replace('\n', '').split(', ')[1:]

        # Go through the item lists and merge them, fill empty spots with fillvalue if there are more items in one of the lists
        this_output_line = []
        for zip_entry in zip_longest(line1_items, line2_items, fillvalue='FILL_VALUE'):
            this_output_line.append(', '.join(zip_entry))
        output_lines.append(', '.join(this_output_line))

    # Write out the file
    with open('./output.txt', 'w') as output_file:
        for line in output_lines:
            output_file.write('%s\n' % line)

如果在合并它们时其中一行中有更多项目，则将 FILL_VALUE 替换为您要插入的任何内容。

如果您需要第一项来自 input2.txt 而不是 input1.txt，line1_items请line2_items在for zip_entry in zip_longest(line1_items, line2_items, fillvalue='FILL_VALUE'):

input2 是每行的第一项将被忽略的地方。

我的测试数据：

输入1.txt：

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
2, 22, 222, 2222

输入2.txt：

z, a, b, c, d, e, f, g, h, i, j, k
z, a, aaa, aaaa

结果：

0, a, 1, b, 2, c, 3, d, 4, e, 5, f, 6, g, 7, h, 8, i, 9, j, 10, k
2, a, 22, aaa, 222, aaaa, 2222, FILL_VALUE
于 2012-08-04T18:13:14.763 回答