c# - WinRT 中的 IPAddress.HostToNetworkOrder() 等效项？

Question

WinRT API 中似乎不存在 IPAddress 类。是否有等效方法IPAddress.HostToNetworkOrder()可用于将 int 从主机顺序转换为网络顺序（小端到大端）？

Answer 1

在许多情况下（当然不是全部），您可以为此使用DataReader和DataWriter：

DataReader reader = new DataReader(stream.AsInputStream());
reader.ByteOrder = ByteOrder.BigEndian;  // standard network byte order
reader.ReadInt16();

出于兼容性原因，我使用了反射器：

    public static short HostToNetworkOrder(short host)
    {
        return (short)(((host & 0xff) << 8) | ((host >> 8) & 0xff));
    }

    public static int HostToNetworkOrder(int host)
    {
        return (((HostToNetworkOrder((short)host) & 0xffff) << 0x10) | (HostToNetworkOrder((short)(host >> 0x10)) & 0xffff));
    }

    public static long HostToNetworkOrder(long host)
    {
        return (long)(((HostToNetworkOrder((int)host) & 0xffffffffL) << 0x20) | (HostToNetworkOrder((int)(host >> 0x20)) & 0xffffffffL));
    }

    public static short NetworkToHostOrder(short network)
    {
        return HostToNetworkOrder(network);
    }

    public static int NetworkToHostOrder(int network)
    {
        return HostToNetworkOrder(network);
    }

    public static long NetworkToHostOrder(long network)
    {
        return HostToNetworkOrder(network);
    }

Answer 2

我最终编写了自己的方法。这真的很简单。它所做的只是颠倒字节顺序。这是为了您的复制和粘贴乐趣：

public static int ReverseEndianness(int num)
{
    byte[] bytes = BitConverter.GetBytes(num);
    byte[] reversedBytes = new byte[bytes.Length];

    for (int i = 0; i < bytes.Length; i++)
    {
        reversedBytes[i] = bytes[bytes.Length - 1 - i];
    }

    return BitConverter.ToInt32(reversedBytes, 0);
}