math - 如何计算“Sn = 11+22+33+...+nn” (N>=1)

Question

如何计算这个系列Sn=1*1+2*2+3*3+...+n*n where (n>1)。
请给我提示

score 6 · Accepted Answer

6

S = n * (n + 1) * (2*n + 1) / 6

It is easy to prove this using induction.

于 2012-08-01T10:33:49.767 回答

score 6 · Accepted Answer

From this page, the following formula can be used

Formula

Please post math questions on http://math.stackexchange.com. SO is for programming-related questions.

math - 如何计算“Sn = 1*1+2*​​2+3*3+...+n*n” (N>=1)