0

我的表如下所示：

表 1：注意：这个表实际上非常大，有更多的列（20ish）和行（以百万计）

 |  Time      |  tmp   |  productionID  |
 |  10:00:00  |   2.2  |    5           |
 |  10:00:05  |   5.2  |    5           |
 |  10:00:11  |   7.4  |    5           |
 |  ......    |   3.2  |    5           |
 |  10:10:02  |   4.5  |    5           |

注意：时间是一个 varchar，所以我假设我需要做这样的事情：

 CONVERT(VARCHAR(8), DATEADD(mi, 10, time), 114)

我需要做的是：

 select time, tmp 
 from mytable
 where productionid = somevalue 
 and time = first_time_stamp associated to some productionID(ie. 10:00:00 table above)
     time = 10 minutes after the first_time_stamp with some productionID
     time = 20 minutes after the first_time_stamp with some productionID
     ...25, 30, 40, 60, 120, 180 minutes

我希望这是有道理的。我不确定这样做的正确方法是什么。我的意思是我想到了以下过程：-选择第一个时间戳（带有一些生产ID）-在那个时间上加10分钟，-加20分钟等等。然后使用数据透视表并使用连接链接到表1必须成为一个更简单的方法。

提前感谢您的专业知识。

预期样本输出：

    |  Time    | tmp
    | 10:00:00 | 2.2 
    | 10:10:02 | 4.5
    | 10:20:54 | 2.3 
    | 10:30:22 | 5.3
4

2 回答 2

1

如果您即时创建间隔表并将其与每个 ProductionID 的开始时间交叉连接，您可以从 MyTable 中提取属于同一类别的记录并选择仅检索第一个。

; with timeSlots (startSlot, endSlot) as (
  select 0, 10
  union all
  select 10, 20
  union all
  select 25, 30
  union all
  select 30, 40
  union all
  select 40, 60
  union all
  select 60, 120
  union all
  select 120, 180
),
startTimes (ProductionID, minTime) as (
  select ProductionID, min([Time])
    from MyTable
   group by ProductionID
),
groupedTime (ProductionID, [Time], [Tmp], groupOrder) as (
  select myTable.ProductionID,
         myTable.Time,
         myTable.Tmp,
         row_number () over (partition by myTable.productionid, timeSlots.startSlot
                           order by mytable.Time) groupOrder
    from startTimes
   cross join timeslots
   inner join myTable
      on startTimes.ProductionID = myTable.ProductionID
     and convert(varchar(8), dateadd(minute, timeSlots.startSlot, convert(datetime, startTimes.MinTime, 114)), 114) <= mytable.Time
     and convert(varchar(8), dateadd(minute, timeSlots.endSlot, convert(datetime, startTimes.MinTime, 114)), 114) > myTable.Time
)
select ProductionID, [Time], [Tmp]
  from groupedTime
 where groupOrder = 1

Sql Fiddle 在这里。

于 2012-07-30T20:54:00.670 回答
0

如果时间没有丢失序列，这将起作用。我的意思是，如果每个 10 分钟的增量都有时间值，那么这将起作用。

create table times([Time] time,tmp float,productionID int)
INSERT INTO times
VALUES('10:10:00',2.2,5),
      ('10:00:05',5.2,5),         
      ('10:00:11',7.4,5),
      ('10:00:18',3.2,5),         
      ('10:10:02',4.5,5),
      ('10:20:22',5.3,5)

select * from times

Declare @min_time time
select @min_time = MIN(time) from times

;WITH times1 as (select row_number() over (order by (select 0)) as id,time, tmp from times where productionID = 5)
,times2 as(
select id,time,tmp from times1 where time=@min_time 
union all
select t1.id,t1.time,t1.tmp from times2 t2 inner join times1 t1 on cast(t1.time as varchar(5))=cast(DATEADD(mi,10,t2.Time) as varchar(5)) --where t1.id-1=t2.id
)

,result as (select MAX(time) as time from times2
group by CAST(time as varchar(5)))

select distinct t2.Time,t2.tmp from times2 t2,Result r where t2.Time =r.time order by 1
于 2012-07-31T12:57:02.887 回答